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zheka24 [161]
3 years ago
15

Please how to solve this problem for grade 2

Mathematics
1 answer:
musickatia [10]3 years ago
3 0

Answer:

1

Step-by-step explanation:

because everytime you turn it you are looking at one face.

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What is the mean of 65,30,25
mixas84 [53]
You've got 3 values there.

Get the sum of 65, 30 and 25 and divide their sum by the number of values that exist, which in this case is 3.

\frac { 65+30+25 }{ 3 } =\frac { 120 }{ 3 } =40

Answer:

40
5 0
3 years ago
Read 2 more answers
An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ = 42 and σ = 5.5.
alexandr1967 [171]

Answer:

a)P( X

We want this probability:

P( X >64)

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X >64) =P(Z> \frac{64-42}{5.5}) =P(Z>4)=0.0000316

b) For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.25   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.674. On this case P(Z<0.674)=0.75 and P(z>0.674)=0.25

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.674

And if we solve for a we got

a=42 +0.674*5.5=45.707

So the value of height that separates the bottom 75% of data from the top 25% is 45.707.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(42,25.5)  

Where \mu=42 and \sigma=5.5

And we want this probability:

P( X

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X

We want this probability:

P( X >64)

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X >64) =P(Z> \frac{64-42}{5.5}) =P(Z>4)=0.0000316

Part b

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.25   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.674. On this case P(Z<0.674)=0.75 and P(z>0.674)=0.25

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.674

And if we solve for a we got

a=42 +0.674*5.5=45.707

So the value of height that separates the bottom 75% of data from the top 25% is 45.707.  

8 0
3 years ago
How do I solve -8=-(x+4)
DiKsa [7]
First do distrubutive property
-(x+4)=-8
Multiply the parenthesis by the invisible -1 in the front 
: -x-4=-8
Now add 4 to both sides
-x=-4
then divide -1 by both sides
x=4 is your answer
8 0
3 years ago
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Graph the function by first finding its zeroes. <br> y = x3- 2x2 + x
CaHeK987 [17]

Answer:

The zeros of the function are;

x = 0 and x = 1

Step-by-step explanation:

The zeroes of the function simply imply that we find the values of x for which the corresponding value of y is 0.

We let y be 0 in the given equation;

y = x^3 - 2x^2 + x

x^3 - 2x^2 + x = 0

We factor out x since x appears in each term on the Left Hand Side;

x ( x^2 - 2x + 1) = 0

This implies that either;

x = 0 or

x^2 - 2x + 1 = 0

We can factorize the equation on the Left Hand Side by determining two numbers whose product is 1 and whose sum is -2. The two numbers by trial and error are found to be -1 and -1. We then replace the middle term by these two numbers;

x^2 -x -x +1 = 0

x(x-1) -1(x-1) = 0

(x-1)(x-1) = 0

x-1 = 0

x = 1

Therefore, the zeros of the function are;

x = 0 and x = 1

The graph of the function is as shown in the attachment below;

8 0
3 years ago
PLEASE ANSWER FAST
neonofarm [45]

Answer:

A. 2.25 and 0.5

B. 1 tomato

6 0
3 years ago
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