Answer with Step-by-step explanation:
We are given that if sum of several numbers is odd
We have to prove that at least one of the number is itself odd.
Suppose, we have three numbers
a=6 , b=7,d=8
Sum of numbers=6+7+8=21=Odd number
We know that sum of two odd numbers is always an even number.
Sum of an odd number and an even number is always an odd number.
If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.
Sum of even numbers is always an even number.
Hence, there are atleast one numebr is odd then the sum of several number is odd.
Answer: 235,000,000
Step-by-step explanation:
Answer:
x = 15 units
Step-by-step explanation:
Here, base of triangle = x units & height = 19 units
Answer:
0.1349
Step-by-step explanation:
Given that:
Sample size, n = 500
20% of 500 ; 0.2 * 500 = 100
p = 0.18 ; n = 500 ; 1 - p = 0.82
P(x ≥ 100) ;
Using the binomial probability relation :
P(x =x) = nCx * p(x)^x * (1 - p)^(n - x
P(x ≥ 100) = 500C100 * 0.18^100 * 0.82^400
P(x ≥ 100) = 0.1349
}
Answer:B
Step-by-step explanation: I said that because you have 27 and 50 Cent so basically you won't have that $5 in that picture because you still going to have that $0.04 and then you still have to have that much so I I think I am right but if I'm not I'm so sorry but I'm taking not even to get I'm trying to get back on track but I think is b for a reason like I think you could be because you have 27 and 50 Cent so if you got twenty-seven fifty cents you just rounding it down
