2 years ago

Find EF in parallelogram CDEF.

Mathematics

1 answer:

Ne4ueva [31]2 years ago

6 0

Answer:

Step-by-step explanation:

EF = CD

FC = DE These equal lines are properties of a parallelogram.

2y = 3y - 17 Add 17 to both sides

2y + 17 = 3y Subtract 2y from both sides.

2y-2y+17 =3y-2y

y = 17

CD = y + 43

CD = 17+43

CD = 60

Since CD = 60 then FE = 60

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10a^2b^0 for a=–3, b=–8

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Step-by-step explanation:

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