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adell [148]
3 years ago
11

Stormer Company reports the following amounts on its statement of cash flow: Net cash provided by operating activities was $40,0

00; net cash used in investing activities was $14,800 and net cash used in financing activities was $17,400. If the beginning cash balance is $6,800, what is the ending cash balance?
Mathematics
1 answer:
Archy [21]3 years ago
8 0

Answer:

its D

Step-by-step explanation:

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Daisy has a pitcher that can hold 1000
mash [69]

Answer:

4.2

Step-by-step explanation:

Divide 1000 by 236 and you will get that result.

7 0
2 years ago
Belle and Mabel are both 8-week-old puppies of different breeds. Belle has a mass of 12
balandron [24]

Answer:

3:1

Step-by-step explanation:

Take the fraction and simplify it:

12/4 = 3/1

6 0
3 years ago
Write an expression for the sequence of operations described below.
Elodia [21]

Answer:

not sure if im right but this is my problem

3b=7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
1) Determine the discriminant of the 2nd degree equation below:
Aleksandr-060686 [28]

\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}

We have, Discriminant formula for finding roots:

\large{ \boxed{ \rm{x =  \frac{  - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a} }}}

Here,

  • x is the root of the equation.
  • a is the coefficient of x^2
  • b is the coefficient of x
  • c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5\pm  \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5  \pm  \sqrt{25 - 24} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 5 \pm 1}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 2 \: or  - 3}}}

❒ p(x) = x^2 + 2x + 1 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{  - 2 \pm  \sqrt{ {2}^{2}  - 4 \times 1 \times 1} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - 2 \pm 0}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x =  - 1 \: or \:  - 1}}}

❒ p(x) = x^2 - x - 20 = 0

\large{ \rm{ \longrightarrow \: x =  \dfrac{ - ( - 1) \pm  \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{1 \pm 9}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \:  - 4}}}

❒ p(x) = x^2 - 3x - 4 = 0

\large{ \rm{ \longrightarrow \: x =   \dfrac{  - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{3 \pm \sqrt{9  + 16} }{2 \times 1} }}

\large{ \rm{ \longrightarrow \: x =  \dfrac{3  \pm 5}{2} }}

So here,

\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \:  - 1}}}

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5 0
3 years ago
Read 2 more answers
Are all congruent rectangles similar?
shusha [124]

All congruent rectangles similar because comparable shapes are not always congruent.

Given that,

We have to find are all congruent rectangles similar.

We know that,

Each side's length and the angles that separate them match those of the other shape's corresponding sides and angles. Comparable shapes are not always congruent, whereas congruent shapes are always similar.

So,

Similar figures are not always congruent, whereas congruent figures are always similar. For similar figures, we simply take into account the shapes, however for congruent triangles, we take into account both the shapes and sizes of the figure.

Therefore, All congruent rectangles similar because comparable shapes are not always congruent.

To learn more about congruent visit: brainly.com/question/26044249

#SPJ4

5 0
1 year ago
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