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adell [148]
3 years ago
11

Stormer Company reports the following amounts on its statement of cash flow: Net cash provided by operating activities was $40,0

00; net cash used in investing activities was $14,800 and net cash used in financing activities was $17,400. If the beginning cash balance is $6,800, what is the ending cash balance?
Mathematics
1 answer:
Archy [21]3 years ago
8 0

Answer:

its D

Step-by-step explanation:

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Maria invests $6,154 in a savings account with a fixed interest rate of 8% compounded continuously. What will the account balanc
Vitek1552 [10]

Answer:

$13,695.98

Step-by-step explanation:

We can use the continuous compound interest formula to solve:

A = Pe^{rt}

<em>P = principal amount</em>

<em>r = interest rate (decimal)</em>

<em>t = time (years)</em>

<em />

First, lets change 8% into a decimal:

8% -> \frac{8}{100} -> 0.08

Now, lets plug in the values:

A=6,154e^{0.08(10)}

A=13,695.98

The account balance after 10 years will be $13,695.98

3 0
3 years ago
Can someone please help me on 20 and 21
Feliz [49]
For number 20 x = 4
3 0
3 years ago
Can someone help me with this problem. I don’t know how to do volume.
densk [106]

Answer:

7.5in³

Step-by-step explanation:

1x5x1.5=7.5

7 0
3 years ago
2. Determine the sum of the first 400 ODD numbers.<br><br>​
il63 [147K]

Odd numbers take the form 2n-1, where n\ge1 is an integer. When n=400, the last odd number would be 799. So we're adding

S=1+3+5+\cdots+795+797+799

By reversing the order of terms, we have

S=799+797+795+\cdots+5+3+1

and we can pair up terms in both sums at the same position to write

2S=(1+799)+(3+797)+(5+795)+\cdots(795+5)+(797+3)+(799+1)

so that we are basically adding 400 copies of 800, and from there we can find the value of the sum right away:

2S=400\cdot800\implies S=160,000

###

We could also make use of the formulas,

\displaystyle\sum_{i=1}^n1=n

\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2

We have

S=\displaystyle\sum_{i=1}^{400}(2i-1)=2\sum_{i=1}^{400}i-\sum_{i=1}^{400}1=400(400+1)-400=400^2=160,000

3 0
4 years ago
3r+n^2-r+5-2n+2 simplify
andrey2020 [161]
3r+n^2-r+5-2n+2=n^2-2n+(3r-r)+(5+2)\\\\=\boxed{n^2-2n+2r+7}
4 0
3 years ago
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