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3 years ago

X=2y+1 solve for y Can someone solve this for me. I’m lowkey slow

Mathematics

2 answers:

saveliy_v [14]3 years ago

7 0

X=2y+1
x-1=2y
y=x/2-1/2

amm18123 years ago

4 0

Answer:

y=x/2-1/2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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Find the length of the base of a square pyramid if the volume is 128 cubic inches and has a height of 6 inches

Len [333]

Answer: a = 8

Step-by-step explanation:

Volume of a square based pyramid is given as

$\frac{a^{2}h }{3}$ .

where a is the length of the side and h is the height.

Substituting into the formula , we have

V = $\frac{a^{2}h }{3}$

128 = $a^{2}h$ /3

384= $a^{2}$ X 6

Divide through by 6

384/6 = $a^{2}$

64 = $a^{2}$

Therefore :

a = $\sqrt{\frac{64}{1} }$

a = 8

6 0

4 years ago

I need help solve please.

gtnhenbr [62]

Answer:

18-4y

Step-by-step explanation:

18 -4y because your start with 18, and each day 4 get eaten. so day 2 (4*2) there will be 8 less, etc, etc

5 0

3 years ago

Using numbers 3 plus 4 times 5 minus 6 divied by 2 equal 32<br><img src="https://tex.z-dn.net/?f=3%20%2B%204%20%5Ctimes%205%20-%

stellarik [79]

31.

3+4 is 7

7 × 5 is 35

35-6 is 29

29 + 2 is 31

4 0

4 years ago

A heat pump cycle whose coefficient of performance is 2.5 delivers energy by heat transfer to a dwelling at a rate of 20 kW.

jasenka [17]

Answer:

Net power = 20kW

B.) $128

Step-by-step explanation:

Given that :

Coefficient of performance = 2.5

Rate = 20kW

The net power required to operate the heat pump :

Energy delivery rate / Coefficient of performance

= 20kW / 2.5

= 8kW

B.) Given that electricity cost equals $0.08 per kW

If pump operates for 200 hours

Total energy used in kWhr :

8kW * 200= 1600kW

Cost per kW = $0.08

1600 * 0.08 = $128

3 0

3 years ago

Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

$\theta=\frac{2\pi}{3},\frac{4\pi}{3}$

7 0

3 years ago