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givi [52]
4 years ago
8

Simplify 8 2(10 – r). a. 7r – 18 b. –2r – 18 c. –2r – 9 d. 28 – 2r

Mathematics
1 answer:
fiasKO [112]4 years ago
8 0
8 + 2(10 - r) = 8 + 20 - 2r = 28 - 2r
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The endpoints of a side of rectangle ABCD in the coordinate plane are at A (3,9) and
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<em>y = - 4x + 38 </em>

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B(5, 1)

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3 years ago
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Answer: each number represents the sum of the two numbers

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3 years ago
Imagine you have some workers and some handheld computers that you can use to take inventory at a warehouse. There are diminishi
Svet_ta [14]

Answer:

a. $1.03

b. $0.93

c. 0.98

d. 2 workers

Step-by-step explanation:

a. Given that:

  • 1 computer : 1 worker : inventory 150 items per hour
  • 1 computer : 2 workers : inventory 200 items per hour
  • 1 computer : 3 workers : inventory 220 items per hour
  • 1 computer : 4+ workers : fewer than 235 items per hour
  • Cost: $100 per computer ; $25 per worker

The fixed production factor in the warehouse is the computer used:

-One computer used, but the number of users is varied to inventory a specified number of items.

-The variable production factor is the number of workers assigned per one computer.

#The cost of inventorying a single item by one worker is:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_1=\frac{125+30}{150}\\\\\\=1.03

Hence, the cost of inventorying a single item is $1.03

b. Using the information provided above, the cost of inventorying a single item when two workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_2=\frac{125+2\times30}{200}\\\\\\=0.925

Hence, the cost of inventorying a single item is $0.93

c.Using the information provided above, the cost of inventorying a single item when three workers are assigned is :

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_3=\frac{125+3\times30}{220}\\\\\\=0.98

Hence, the cost of inventorying a single item is $0.98

d. To determine the most cost-effective job assignment, we calculate the cost of 4+ workers.

Take any number less than 235(say 234) as the inventory units:

Cost=\frac{C_{pc}+Wage}{Items} \ , C_{pc}=\$125\\\\Cost_4=\frac{125+4\times30}{234}\\\\\\=1.05

From our calculations, it's clear that two workers per computer costs the least amount($0.93) per unit item. Hence, it is best to assign two workers per computer.

4 0
3 years ago
A map of your town has a scale of 1 inch to 0.25 mile. There are two roads that are 5 inches apart on the map. What is the actua
tatiyna
If 1 inch is .25 miles then all you have to do is multiply .25 miles by 5 inches and u get 1.25 miles.
4 0
3 years ago
Read 2 more answers
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