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Nikitich [7]
3 years ago
14

1.1.3 what is the the perimeter of a swimming pool if the length is 4,5m and the breadth is 3m? 1.1.4 Define the following conce

pts :a. Ratio. b. Rate​
Mathematics
1 answer:
kvv77 [185]3 years ago
7 0

Step-by-step explanation:

please subscribe to my mom channel please

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Find all solutions in the interval [0, 2π). tan x + sec x = 1
svp [43]
Use the identity 
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x  = 1 + tan^2x - 2 tan x
0 = -2 tanx 

tan x = 0 

x =  0, π 
π is an extraneous root because sec 180 = -1 
So the answer  is 0 degrees
6 0
3 years ago
A 4-pack of frappuccino’s costs $10.88 how much does each individual can cost
Aleks04 [339]

Answer:

$ 2.72

Step-by-step explanation:

divide 10.88 by 4

7 0
3 years ago
On a horizontal number line, 6 is located to the<br> of -4. So, -6 is<br> than-4
bogdanovich [222]

On a horizontal number line, -6 is located to the (left) of -4. So, -6 is (less than) 4.

7 0
3 years ago
Help me please (no links please)
stich3 [128]

a) This part is already complete I think..

b) This is a cuboid and lateral surface area of cuboid is: 2(lb +bh + hl)

= 2( 10 × 3 + 3 × 7 + 7 × 10)

= 2(30 + 21 + 70)

= 2 × 121 = 242 cm²

Now, the area of top & bottom: lb

= 2 × 10 × 3

= 60 cm²

Neglecting the top & bottom surface area of cuboid:

= 242 - 60

= 180 cm²

c) The total surface area us 242.. I have already done that part above...

__________________________

If i have done something wrong.. please lemme know :)

7 0
2 years ago
What's is the converse of the statement?If x is odd, then 2x is even.
dsp73
If you have two statements p and q and p\Rightarrow q is true, then  \neg q\Rightarrow \neg p is also true.

In your case, statements are p - "x is odd" and q -  "2x is even".

 Then \neg p - "x is not odd" and \neg q - "2x is not even."


Hence \neg q\Rightarrow \neg p sounds as: "If 2x is not even, then x is not odd".
Answer: correct choice is D.







7 0
3 years ago
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