The two base angles of an isoceles triangle are equal so we can conclude that
2x - 20 = x + 8
Now we just need to solve for x:
2x - 20 + 20 = x + 8 + 20
2x = x + 28
2x - x = x + 28 - x
x = 28
So, angle B = x + 8 which is 28 + 8 = 36°
Answer:
Solving the system of equations:
x: 1
y: 2
Step-by-step explanation:
Plug it in to see if it is right, to make sure of course. Better to be safe than sorry.
8e^(4x)×2e^(5x-1)
16e^(4x+5x-1)
When bases are same power adds.
16e^(9x-1)
Answer:
x = 17
y = 8
QPR = 35º
QRP = 60º
Step-by-step explanation:
2x + 1 = x + 18
Subtract x from both sides
x + 1 = 18
Subtract 1 from both sides
x = 17
QPR = 2x + 1
QPR = 2(17) + 1
QPR = 35º
-------------------------------
8y - 4 = 4y + 28
Subtract 4y from both sides
4y - 4 = 28
Add 4 to both sides
4y = 32
Divide both sides by 4
y = 8
QPR = 8y - 4
QRP = 8(8) - 4
QRP = 60º
