Question

The surface area of a right square pyramid is given by A=b2+2bh where b is the length of a side of the base and h is the slant height.solve the formula for h if b=3

Answer 1

Answer:

$h = \dfrac{A - 9}{6}$

Step-by-step explanation:

A=b^2+2bh

b = 3

A = 3^2 + 2(3)h

A = 9 + 6h

6h = A - 9

$h = \dfrac{A - 9}{6}$