Answer:
answer is A but im sure you've gotten it by now
Step-by-step explanation:
Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
<span>3/4x - 4/5 = 1/2x + 1
</span>3/4x - 4/5 = 2/4x + 1
3/4x - 2/4x = 1 + 4/5
1/4x = 9/5
x = (9x4) / (5x1)
x = 36/5
x = 7 1/5
