Answer:
The probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license is 0.32.
Step-by-step explanation:
Denote the events as follows:
<em>X</em> = a fisher at Clearwater Park had a fishing license
<em>Y</em> = a fisher at Mountain View Park had a fishing license
The two events are independent.
The information provided is:
n (X) = 48
n (X') = 32
n (Y) = 72
n (Y') = 18
Then,
N (X) = n (X) + n (X')
= 48 + 32
= 80
N (Y) = n (Y) + n (Y')
= 72 + 18
= 90
Compute the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license as follows:


Thus, the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license is 0.32.
We must solve <span>2/5 ≥ w -3/5. Note that w is already +, so leave it where it now is. Add 3/5 to both sides of this inequality:
2/5 + 3/5 </span>≥ w - 3/5 + 3/5
Then: 1 ≥ w, or w ≤ 1 (answer)
Answer:
6
/5
Step-by-step explanation: