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nata0808 [166]
3 years ago
7

What is the value of sec(-30°)?

Mathematics
1 answer:
Vadim26 [7]3 years ago
3 0

Answer:

\frac{2.\sqrt{3} }{3}

Step-by-step explanation:

Sec = 1/cos

Using the above identity, we can write the given sec(-30) as

sec(-30) = 1/ cos(-30)

On the trigonometric unit circle.

cos(-30) = cos(30) = \frac{\sqrt{3} }{2}

Therefore,

sec(-30) = 1/cos(-30) = 1/cos(30)

Now plug in cos(30) = √3/2

sec(-30) = 1/ (√3/2)

= 1 * 2/√3

= 2/√3

Since we have radical number in the denominator, so we can multiply both the numerator and the denominator by √3.

= (2*√3) /(√3*√3)

= 2√3 /3

Answer: \frac{2.\sqrt{3} }{3}

Hope you will understand the concept.

Thank you.

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