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3 years ago

There is $100 it goes up 10% how much is it

2 answers:

8 0

To find this is asking what is 10% of 100. Remember that in word problems of always means *(multiply). So that means that we need to multiply 100 times 10%, or
.10. So 100 times .10 is 10. If 10 is 10% of 100, then you need to add the extra 10% to the original number. So add 10 + 100. Now the answer would be $110. Hope this helps

Umnica [9.8K]3 years ago

5 0

Its 110 cuz it goes up 10% if it was 20% it would be 120

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3 years ago

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krok68 [10]

One way to capture the domain of integration is with the set

$D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}$

Then we can write the double integral as the iterated integral

$\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx$

Compute the integral with respect to $y$ .

$\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)$

Compute the remaining integral.

$\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}$

We could also swap the order of integration variables by writing

$D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}$

and

$\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy$

and this would have led to the same result.

$\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)$

$\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)$

7 0

1 year ago

Solve 7x − 2y = −3<br> 14x + y = 14

Sauron [17]

7x - 2y = -3

14x + y = 14
14x -14x + y = 14-14x
Y = 14 - 14x

7x -2y = -3
7x - 2(14 - 14x) = -3
7x -28 + 28x = -3
7x + 28x - 28 = -3
35x - 28 = -3
35x - 28 + 28 = -3 + 28
35x = 25
35x/35 = 25/35
X = 25/35 = 5/7.

Y = 14 - 14x
Y = 14 - 14(5/7)
Y = 14 - 10
Y = 4.

The solution P(5/7,4).

8 0

3 years ago

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