The third term is 9
t(3)=2(3)+3
6+3 = 9
Answer:
The probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.
Step-by-step explanation:
Let <em>X</em> = number of students arriving at the 10:30 AM time slot.
The average number of students arriving at the 10:30 AM time slot is, <em>λ</em> = 3.
A random variable representing the occurrence of events in a fixed interval of time is known as Poisson random variables. For example, the number of customers visiting the bank in an hour or the number of typographical error is a book every 10 pages.
The random variable <em>X</em> is also a Poisson random variable because it represents the fixed number of students arriving at the 10:30 AM time slot.
The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.
The probability mass function of <em>X</em> is given by:

Compute the probability of <em>X</em> = 2 as follows:

Thus, the probability that in a randomly selected office hour in the 10:30 am time slot exactly two students will arrive is 0.2241.
Answer:
Step-by-step explanation:The solution is x > 3
<span>11+4 (x+7)^2
Substitue 2 for x
</span><span>11+4 (2+7)^2
Multiply the numbers inside of the parenthesis by the exponent
11+4 (4+49)
Add 4 to 59
11+4 (54)
Add 4 to 11
15(54)
Multiply
Final Answer: 810</span>