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Lynna [10]
3 years ago
15

Last year 40 people adopted a manatee through Fias Foundation. This year 30%more people adopted a manetee.How many more people a

dopted a manatee
Mathematics
1 answer:
Nastasia [14]3 years ago
5 0
The answer is 12.
40✖️0.30 = 12.

Therefore 12 more people adopted a manatee. Hope this helps
You might be interested in
Select the type of equations
olya-2409 [2.1K]
Two lines are "inconsistent" if they are parallel. They are "equivalent" if they are the same line. Otherwise, they are "consistent."

Your first 3 graphs show "consistent" equations.

The 4th graph shows "inconsistent" equations.

The solution shown on the 5th graph is where the lines intersect, near point
  (5, 3)
4 0
3 years ago
Read 2 more answers
One eighth of a number is less than or equal to 3 what is the inequality
Elodia [21]
We will assume that the number is n
one eighth of the number = 1/8 x n = n/8
we know that this result n/8) is less than or equal (<=) 3
therefore, the inequality is:
n/8 <= 3
8 0
3 years ago
The polynomial P(x) = 2x^3 + mx^2-5 leaves the same remainder when divided by (x-1) or (2x + 3). Find the value of m and the rem
Zigmanuir [339]

Answer:

m=7

Remainder =4

If q=1 then r=3 or r=-1.

If q=2 then r=3.

They are probably looking for q=1 and r=3 because the other combinations were used earlier in the problem.

Step-by-step explanation:

Let's assume the remainders left when doing P divided by (x-1) and P divided by (2x+3) is R.

By remainder theorem we have that:

P(1)=R

P(-3/2)=R

P(1)=2(1)^3+m(1)^2-5

=2+m-5=m-3

P(\frac{-3}{2})=2(\frac{-3}{2})^3+m(\frac{-3}{2})^2-5

=2(\frac{-27}{8})+m(\frac{9}{4})-5

=-\frac{27}{4}+\frac{9m}{4}-5

=\frac{-27+9m-20}{4}

=\frac{9m-47}{4}

Both of these are equal to R.

m-3=R

\frac{9m-47}{4}=R

I'm going to substitute second R which is (9m-47)/4 in place of first R.

m-3=\frac{9m-47}{4}

Multiply both sides by 4:

4(m-3)=9m-47

Distribute:

4m-12=9m-47

Subtract 4m on both sides:

-12=5m-47

Add 47 on both sides:

-12+47=5m

Simplify left hand side:

35=5m

Divide both sides by 5:

\frac{35}{5}=m

7=m

So the value for m is 7.

P(x)=2x^3+7x^2-5

What is the remainder when dividing P by (x-1) or (2x+3)?

Well recall that we said m-3=R which means r=m-3=7-3=4.

So the remainder is 4 when dividing P by (x-1) or (2x+3).

Now P divided by (qx+r) will also give the same remainder R=4.

So by remainder theorem we have that P(-r/q)=4.

Let's plug this in:

P(\frac{-r}{q})=2(\frac{-r}{q})^3+m(\frac{-r}{q})^2-5

Let x=-r/q

This is equal to 4 so we have this equation:

2u^3+7u^2-5=4

Subtract 4 on both sides:

2u^3+7u^2-9=0

I see one obvious solution of 1.

I seen this because I see 2+7-9 is 0.

u=1 would do that.

Let's see if we can find any other real solutions.

Dividing:

1     |   2    7     0     -9

     |         2      9      9

       -----------------------

          2    9     9      0

This gives us the quadratic equation to solve:

2x^2+9x+9=0

Compare this to ax^2+bx+c=0

a=2

b=9

c=9

Since the coefficient of x^2 is not 1, we have to find two numbers that multiply to be ac and add up to be b.

Those numbers are 6 and 3 because 6(3)=18=ac while 6+3=9=b.

So we are going to replace bx or 9x with 6x+3x then factor by grouping:

2x^2+6x+3x+9=0

(2x^2+6x)+(3x+9)=0

2x(x+3)+3(x+3)=0

(x+3)(2x+3)=0

This means x+3=0 or 2x+3=0.

We need to solve both of these:

x+3=0

Subtract 3 on both sides:

x=-3

----

2x+3=0

Subtract 3 on both sides:

2x=-3

Divide both sides by 2:

x=-3/2

So the solutions to P(x)=4:

x \in \{-3,\frac{-3}{2},1\}

If x=-3 is a solution then (x+3) is a factor that you can divide P by to get remainder 4.

If x=-3/2 is a solution then (2x+3) is a factor that you can divide P by to get remainder 4.

If x=1 is a solution then (x-1) is a factor that you can divide P by to get remainder 4.

Compare (qx+r) to (x+3); we see one possibility for (q,r)=(1,3).

Compare (qx+r) to (2x+3); we see another possibility is (q,r)=(2,3).

Compare (qx+r) to (x-1); we see another possibility is (q,r)=(1,-1).

6 0
3 years ago
What number when multiplied by 5 is one third of the sum of 64 and 56?​
Nookie1986 [14]

Answer:

8

Step-by-step explanation:

Create an expression to model the situation. One can do this by simply rewriting the written expression in terms of numbers and variables. Use the variable (x) to represent the unknown value.

5(x)=\frac{1}{3}(64+56)

Simplify this expression,

5(x)=\frac{1}{3}(64+56)\\5x=\frac{1}{3}(120)\\5x=40\\

Use inverse operations to solve for (x),

5x=40\\x=8

6 0
3 years ago
Find the volume of this cylinder. Use 3 for .<br> 10 in<br> V = r2h<br> 11 in<br> V [?]in
eduard

Answer:

825 in^3

Step-by-step explanation:

The volume of a cylinder is

V = pi r^2 h  where r is the radius and h is the height

We are given the diameter of 10

The radius is 1/2 of the diameter of 1/2 (10) = 5

V = (3) * (5)^2 * 11

V = 3( 25)*11

   = 825 in^3

3 0
3 years ago
Read 2 more answers
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