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<h2>Y=1/2x-1</h2>Find where the expression
1/2x−1 is undefined.
x=1/2
Consider the rational function
R(x)=ax^n/bx^m where n is the degree of the numerator and m is the degree of the denominator.
1. If n<m, then the x-axis, y=0, is the horizontal asymptote.
2. If n=m, then the horizontal asymptote is the line y = ab.
3. If n>m, then there is no horizontal asymptote (there is an oblique asymptote).
Find n and m.n=0m=1
Since n<m, the x-axis, y=0, is the horizontal asymptote.y=0
There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes
This is the set of all asymptotes.
Vertical Asymptotes:
x=1/2
Horizontal Asymptotes:
y=0
No Oblique Asymptotes
<h2>2x+y=4</h2>Subtract 2x from both sides of the equation.
y=4−2x
Rewrite in slope-intercept form.
The slope-intercept form is
y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Reorder 4 and −2x.
y=−2x+4
Use the slope-intercept form to find the slope and y-intercept.
Find the values of m and b using the form
y=mx+b.
m= - 2b=4
The slope of the line is the value of m, and the y-intercept is the value of b.
Slope: −2
y-intercept: (0,4)
Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y
values.
Find the x-intercept.
x-intercept(s):
(2,0)
Find the y-intercept.
y-intercept(s):
(0,4)
Create a table of the x and y values.
x y
0 4
2 0
Graph the line using the slope and the y-intercept, or the points.
Slope: −2
y-intercept:
(0,4)
Step-by-step explanation:
Hope it is helpful...
<u>Answer-</u>
<u>Solution-</u>
The equation for time period of a simple pendulum is given by,
Where,
T = Time period,
L = Length of the rod,
g = Acceleration due to gravity.
Frequency (f) of the pendulum is the reciprocal of its period, i.e
Putting the values,