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2 years ago

Expand the brackets 2x(3x+5).

Mathematics

1 answer:

Harrizon [31]2 years ago

5 0

Answer:

6x²+10x

Step-by-step explanation:

2x(3x+5)

Distribute 2x to the terms in the bracket.

2x(3x) + 2x(5)

2x × 3x + 2x × 5

Multiply the terms.

6x²+10x

The answer is 6x²+10x.

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What is the equation for a line with a slope of -1/3 and a y-intercept of -5?

garri49 [273]

Answer:

y=-1/3x-5

Step-by-step explanation:

y=mx+b is equation of line where m is slope and b is y-intercept.

From question statement, we observe that

m= -1/3 , b= -5

put above values in equation of line, we get

y= -1/3x-5.

3 0

2 years ago

Come quic 5 qts .. pics provided !! answer correctly plz!!

adelina 88 [10]

Answer:

First Picture: -2/7

Second Picture: 9/5

Third Picture: 5/3

Not sure of the others

Step-by-step explanation:

Pick two points on the line and determine their coordinates.

Determine the difference in y-coordinates of these two points (rise).

Determine the difference in x-coordinates for these two points (run).

Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).

7 0

2 years ago

Read 2 more answers

What is the slope of the line x=-3

mote1985 [20]

x = 3 is a vertical line that goes straight up and down at 3 on the x axis, vertical lines have a undefined slope. Don't confuse that with no slope which is a flat like like y=7.

so the slope is undefined

4 0

2 years ago

Read 2 more answers

23n=2.4 A. 3.6 B. 7.2 C. 1.2 D. 1.6

svp [43]

$\huge\text{Hey there!}$

$\mathsf{23n =2.4}$

$\large\text{DIVIDE 23 to BOTH SIDES}$

$\mathsf{\dfrac{23n}{23}=\dfrac{2.4}{23}}$

$\large\text{Cancel out: }\mathsf{\dfrac{23}{23}}\large\text{ because it gives you 1}$

$\large\text{Keep: }\mathsf{\dfrac{2.4}{23}}\large\text{ because it helps us solve for n}$

$\mathsf{n = \dfrac{2.4}{23}}$

$\mathsd{\dfrac{2.4}{23}= 2.4\div 23\rightarrow \bf 0.104348}$

$\boxed{\boxed{\large\textsf{Answer: \huge n = \bf 0.104348}}}\huge\checkmark$

$\boxed{\textsf{NONE OF THE ABOVE is your ANSWER}}$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

8 0

2 years ago

write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o

Alenkinab [10]

$\bf f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}\\\\
f(x)=&{{ A}} \left|{{ B }}x+{{ C}} \right|+{{ D}}
\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see,

$\bf f(x)=|x| \implies \begin{array}{lllccll}
f(x)=&1|&1x&+0|&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.

5 0

2 years ago