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3 years ago

Simplify 6 - 2 3 + (-9 + 5) · 2.

Mathematics

2 answers:

Lapatulllka [165]3 years ago

7 0

I think the answer is -25

Licemer1 [7]3 years ago

4 0

Answer: -25

Hope this helps! <3

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The graph shows how the volume, V, of the cube changes as the length of the sides, S, changes

Artemon [7]

Solution:

The graph shows how the volume, V, of the cube changes as the length of the sides, S, changes.

On analysing the graph ,

$\left\begin{array}{ccc}s&v\\0&0\\2&1\\4 &8\end{array}\right$

This table shows how the volume, V, of the cube changes as the length of the sides, S, changes.

Option C is the correct option for the table that matches the graph.

7 0

4 years ago

Read 2 more answers

Calculate the slope of the line that passes through (12,15) and (10, 21). Reduce answer to lowest terms if

gulaghasi [49]

Answer:

-3

Step-by-step explanation:

Slope is rise divided by run. Y2-Y1 Divided by X2-X1

You get 6 divided by -2

-3

3 0

3 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

4 years ago

Find the area of the figure to the nearest tenth.

ad-work [718]

Answer: 31.3 square feet

Step-by-step explanation:

6 0

2 years ago

If x = 1 is a common root of ax² +ax + 2 = 0 and x² + x + b = 0 , then ab =

vodka [1.7K]

Answer:

ab = 2

Step-by-step explanation:

Given equations

ax² +ax + 2 = 0

x² + x + b = 0

root of both the equation

x= 1

then we can plug in x = 1 in both the equation

ax² +ax + 2 = 0 x² + x + b = 0

a*1² +a*1 + 2 = 0 1² + 1 + b = 0

a +a + 2 = 0 1 + 1 + b = 0

2a + 2 = 0 2 + b = 0

2a = - 2 b = -2

a = -2/2 = -1

Thus,

a = -1

b = -2

a*b = -1*-2 = 2

ab = 2

6 0

3 years ago