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2 years ago

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The cost of a square slab is proportional to its thickness and also proportional to the square of its length. What is the cost o

f a square slab that is 3 meters long and 0.1 meter thick?
(1) The cost of a square slab that is 2 meters long and 0.2 meter thick is $160 more than the cost of a square slab that is 2 meters long and 0.1 meter thick.

(2) The cost of a square slab that is 3 meters long and 0.1 meter thick is $200 more than the cost of a square slab that is 2 meters long and 0.1 meter thick.

2 answers:

Alex73 [517]2 years ago

8 0

Answer:

$520

Explanation:

Using information provided in the question, equations can be formed to determine the unknown proportionality factors.

$C=AT + BL^2$ , where C is the cost, T is the thickness, L is the length and A and B are the proportionality factors

Equation 1:

Slab 1: $C_1=0.2A + 2^2B=0.2A+4B$

Slab 2: $C_2=0.1A + 2^2B=0.1A+4B$

$C_1=C_2+160$

$0.2A+4B=0.1A+4B+160$

$0.1A=160$

$A=1600$

Equation 2:

Slab 2: $C_2=0.1A + 3^2B=0.1A+9B$

Slab 3: $C_3=0.1A + 2^2B=0.1A+4B$

$C_2=C_3+200$

$0.1A+9B=0.1A+4B+200$

$5B=200$

$B=40$

After determining unknowns A=1600 and B=40, these can be substituted into $C=AT + BL^2$ to give below

$C=1600T + 40L^2$

Cost is to be determined for T=0.1m and L=3m

$C=1600T + 40L^2$

$C=1600(0.1) + 40(3)^2$

$C=160 + 360$

$C=520$

The cost of a square slab of 3 meter length and 0.1 meter thickness is $520

otez555 [7]2 years ago

5 0

Answer:

(1) The cost of the square slab is $360

(2) The cost of the square slab is $360

Explanation:

Cost (C) varies as thickness (t) and square of length (L^2)

Therefore, C = ktL^2

Case 1

C1 = 160 + C2

C1 - C2 = 160

C1 = ktL^2 (t = 0.2, L = 2)

C1 = k×0.2×2^2 = 0.8k

C2 = ktL^2 (t = 0.1, L = 2)

C2 = k×0.1×2^2 = 0.4k

C1 - C2 = 0.8k - 0.4k = 0.4k

C1 - C2 = 0.4k

160 = 0.4k

k = 160/0.4 = 400

C = ktL^2 (t = 0.1, t = 3)

C = 400×0.1×3^2 = $360

Case 2

C1 = 200 + C2

C1 - C2 = 200

C1 = ktL^2 (t = 0.1, L = 3)

C1 = k×0.1×3^2 = 0.9k

C2 = ktL^2 (t = 0.1, L = 2)

C2 = k×0.1×2^2 = 0.4k

C1 - C2 = 0.9k - 0.4k = 0.5k

C1 - C2 = 0.5k

200 = 0.5k

k = 200/0.5 = 400

C = ktL^2 (t = 0.1, L = 3)

C = 400×0.1×3^2 = $360

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White raven [17]

Answer:

False

Explanation:

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The amount a taxpayer has at risk is increased by the taxpayer's income and decreased by the share of losses and withdrawal from the activity. For partnership, the at risk increases with an increase in debt and vice versa.

Jack's year-end at-risk amount = At risk amount - (interest *loss) = $42,000 - (10% × $60,000 loss) = $36,000

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Answer:

<u>Part(a) Differential analysis as at February 24</u>

Make (Alternative 1) :

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Variable Overheads $2.70

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Total Make Costs $55.70

Buy (Alternative 2) :

Total Purchase Cost $59.00

<u>(b) On the basis of the data presented, would it be advisable to make the carrying cases or continue buying them? </u>

It is clear that from comparison of the cost of Purchase and the Cost of Making the Carrying Cases, the Cost of Making the Carrying Cases is lower than the Cost of Purchasing the Cases by $3.30

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3 years ago

assume that monty completed the office and warehouse building on december 31, 2020, as planned at a total cost of $7,280,000, an

Eva8 [605]

Answer:

AI = $1,424,864

Hence, the avoidable interest for the Monty's project is $1,424,864.

Explanation:

Note: This question is incomplete and lacks necessary data to answer this question. But I have found similar question on the internet and will be using its data in this question to answer for the sack of concept and understanding. Thank you!

Data Given:

Total Cost = $7,280,000

Weighted-Average amount = $5,040,000

We need to compute the avoidable interest on this project.

Data Missing:

Construction loan amount = $2,800,000

Construction loan Interest Rate = 12%

Construction loan Time period = Semi-Annually.

Construction loan Issued = 31 Dec, 2019

Short-term loan amount = $1,960,000

Short-term loan interest 10%

Short-term loan Time period = Monthly payable

Short-term loan Maturity period = 30 May, 2021

Long-term loan amount = $1,400,000

Long-term loan interest rate = 11%

Long-term loan Time period = Annually on 1st January

Long-term loan Principal Payable = 1 Jan, 2024

Solution:

Now, this question is complete and can be solved.

First of all, we need to calculate the general borrowings in construction of the building.

Let X be the general borrowings in construction of the building.

Let Y be Weighted average

Let Z be the Construction for whole year

Where, Y = $5,040,000

Z = $2,800,000

So,

X = Y - Z

X = $5,040,000 - $2,800,000

X = $2,240,000 (This is the general borrowings)

Now, we have to calculate the weighted average interest rate in order to calculate the avoidable interest on this project.

Weighted average interest rate = (Short term loan interest rate x short term loan amount divided by Sum of total loan including short and long) + (long term load interest rate x long term loan amount divided by the sum of total loan)

Let A be the Weighted average interest rate.

So,

A = (10 * $1,960,000/($1,960,000 + $1,400,0000) + ($11% * $1,400,000/($1,960,000 + $1,400,0000) )

A = 48.61%

Now, we just have to put in the values to find out the avoidable interest.

Let Avoidable interest = AI

AI = ($2,800,000 x 0.12) + ($2,240,000 x 0.4861)

AI = $1,424,864

Hence, the avoidable interest for the Monty's project is $1,424,864.

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3 years ago

Last year, a women's professional organization made two small-business loans totaling $23,000 to young women beginning their own

Fittoniya [83]

Answer:

a. Loan amount at 9%=5,000

b. Loan amount at 11%=$18,000

Explanation:

To determine the amount of each loan amount, first we need to derive the following equations;

a.

<em>Step 1: Determine loan amount at 9%</em>

Total Interest=Interest from 9%+interest from 11%

where;

Total interest=$2,430

Interest from 9%=principal amount at 9%×interest rate×number of years

Interest from 11%=principal amount at 11%×interest rate×number of years

and;

Principal amount at 9%=x, interest rate=9/100=0.09, number of years=1

Principal amount at 11%=23,000-x, interest rate=11/100=0.11, number of years=1

replacing;

2,430=(x×0.09×1)+0.11(23,000-x)

2,430=0.09 x+2,530-0.11 x

(0.11 x-0.09 x)=2,530-2,430

0.02 x=100

x=100/0.02

x=5,000

Loan amount at 9%=5,000

b.

<em>Step 2: Determine loan amount at 11%</em>

Use the expression below to determine the loan amount at 11%;

Loan amount at 11%=Total loan amount-loan amount at 9%

where;

Loan amount at 11%=unknown, to be determined

Total loan amount=$23,000

Loan amount at 9%=$5,000

replacing;

Loan amount at 11%=23,000-5,000=$18,000

Loan amount at 11%=$18,000

3 0

3 years ago

The unadjusted trial balance at year-end for a company that uses the percent of receivables method to determine its bad debts ex

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Answer:

The adjusting entry which is to be recorded is shown below:

Explanation:

The adjusting entry which is to be recorded is as:

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Allowance for Doubtful Accounts A/c...............Cr $14,740

As the company records the bad debt expense at the end of the present year

Working Note:

As the company used the percent of receivables sales

Amount = Accounts receivables × Percentage of ending receivable

= $446,000 × 3.0%

= $13,380

Bad debt expense amount = Amount - Debit balance of allowance for doubtful accounts

= $13,380 + $1,360

= $14,740

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3 years ago