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Eddi Din [679]
3 years ago
7

What is an equation of the line that passes through the point (2, -6) and is parallel

Mathematics
1 answer:
fomenos3 years ago
5 0

Answer: y=-6

Step-by-step explanation:

First convert the equation -2y= 8 into y intercept form by divide both sides by -2.

-2y = 8  

y= -4     Now that the line is in y intercept form we can now determine the slope.The slope is 0  so -4 in this case is the y intercept.

Remember lines that a parallel needs to have the same slope but different y-intercepts.

So if the slope of the line y=-4 is 0 then the slope of line that passes through the point (2,-6)  

So using the y intercept form formula which says that y=mx+b where m is the slope and b is the y-intercept, we could plot in the values for y and x and solve for b to write the equation.

y is -6 and x is 2

-6 = 0(2) + b

-6 = 0 + b

b= -6  

In this case the y intercept is -6 so since the slope is zero we will have the equation  y = -6  

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The derivative of y with respect to x, when y = 3e^5x - 2 is:
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Step - by - step

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Replace
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Multiply 5 by 3
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Since -2 is constant with respect to x, the derivative of -2 with respect to x is 0.
15e^5x + 0
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