First you must know that is i∧2= -1
x∧3-4x∧2+4x-16 = x∧2 (x-4) + 4 (x-4) = (x-4) (x∧2+4) = (x-4) (x∧2-(-4)) =
= (x-4) (x∧2-(-1) *4) = (x-4) (x∧2- i∧2*2∧2) = (x-4) (x∧2-(2i)∧2) = (x-4) (x-2i) (x+2i)
Good luck!!!
It’s 4 so ye it’s ez so ye bye
Remember PEMDAS:
The answer is <span>106.72.</span>
