Answer:
The probability of randomly selecting a rod that is shorter than 22 cm
P(X<22) = 0.1251
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given mean of the Population = 25cm
Given standard deviation of the Population = 2.60
Let 'x' be the random variable in normal distribution
Given x=22
<u><em>Step(ii):</em></u>-
The probability of randomly selecting a rod that is shorter than 22 cm
P(X<22) = P( Z<-1.15)
= 1-P(Z>1.15)
= 1-( 0.5+A(1.15)
= 0.5 - A(1.15)
= 0.5 - 0.3749
= 0.1251
The probability of randomly selecting a rod that is shorter than 22 cm
P(X<22) = 0.1251
Answer: fluffy = 33yrs
Spot = 19 yrs
Skampy = 39 yrs
Step-by-step explanation:
Let fluffy = x
Spot = y
Skampy =z
x + y + z = 91 -------1
x -14 =y ------2
z = x + 6 --------3
Put eqn 2 and 3 in eqn 1
x + x - 14 + x + 6 = 91
3x = 99
x = 33
y = 33-14= 19
z = 33+6 = 39
Answer:
72 sq. mi
Step-by-step explanation:
Breaking this down, we have 2 right triangles with sides of 3, 4, and 5 miles, and 3 rectangles with dimensions 3 x 5, 4 x 5, and 5 x 5 miles. Remember that the area of a triangle is 1/2 x b x h , where b and h are the triangle's base and height. The base and height of the triangles at the bases of the figure are 3 and 4, so each triangle has an area of 1/2 x 3 x 4 = 1/2 x 12 = 6 sq. mi, or 6 + 6 = 12 sq. mi together.
Onto the rectangles, we can find their area by multiplying their length by their width. Since the width of these rectangles is the same for all three - 5 mi - we can make our lives a little easier and just "glue" the lengths together, giving us a longer rectangle with a length of 3 + 4 + 5 = 12 mi. Multiplying the two, we find the area of the rectangles to be 5 x 12 = 60 sq. mi.
Adding this area to the triangle's area gives us a total area of 12 + 60 = 72 sq. mi.
Answer:
13 and 23
Step-by-step explanation:
create an equation to solve:
(2x-3) + x = 36
3x - 3 = 36 combine like terms
<u> +3 +3</u><u> </u> add 3 to both sides
<u>3</u>x = <u>39</u>
3 3 divide both sides by 3
x = 13
<u>13 is the first number</u>
the 2nd number is 3 let than twice the first so we create and solve a new equation:
2x - 3 = ?
2(13) = ? substitute 13 from the
smaller number to solve
<u>23 = the 2nd number</u>
The first equation is $3 times 9 = $27 the next equation iis $1 times 2 = $1
So you do 9 transactions over $100 and 2 transactions of $100 or lower.
