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Lelechka [254]
3 years ago
8

How does the area of triangle ABC Compare to the area of parallelogram ghjk

Mathematics
2 answers:
skad [1K]3 years ago
8 0

Answer:

Area of parallelogram divided by 2 is the triangles are.

Area of parallelogram = B x H and triangle area = 1/2 x B x H

Step-by-step explanation:

Evgen [1.6K]3 years ago
6 0

Answer:

A ) The area of Δ ABC is 2 units greater than area of parallelogram GHJK.

Step-by-step explanation:

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Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{4 {x}^{3}  + 6 {y}^{2} }}}}}

Step-by-step explanation:

\sf{5 {y }^{2}  + 5 - 4 - 4 {y}^{2}  + 5 {y}^{2}  - 4 {x}^{3}  - 1}

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⇒\sf{4 {x}^{3}  + 6 {y}^{2}  + 1 - 1}

⇒\sf{4 {x}^{3}  + 6 {y}^{2} }

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