Answer:
x<_2
Step-by-step explanation:
first off solve this like a regular equation the >_ dosent matter till later
so basically first multiply - by 13 and -x so you get -13 and x (multiplying two negatives = a positive)
so its 5x-13+x>_9x-7
add 5x and x to get 6x-13 on one side
then you get 6x-13>_9x-7 then subtract -9x from both sides
so its now -3x-13>_-7 add 13 so you get -3x>_6
then divide both sides by -3 (when you divide an equation with a >< or <_ >_ by a negative number that sign switches) so it will now be x<_2
that your final answer hope this helps :)
