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Fofino [41]
3 years ago
7

Any of the distinct objects of a set is called a(n)____

Mathematics
1 answer:
Hatshy [7]3 years ago
4 0
Any of the distinct objects of a set is called an element of the set



hope this help u
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A person purchased a leather jacket that was marked down by 40%. if the sale price of the jacket was $101.79, what was its origi
Rama09 [41]
The original price was $142.50. What I did was that I added 40% with $101.79 which was the sales price. With the 40% the person saved $40.71.

Hope this helps : )*****
5 0
3 years ago
The function f given by f(x) =9x^(2/3) +3x-6 has a relative minimum at x=?.
Phoenix [80]
<span>f '(x) = 6/(x^1/3) + 3 = 0 

x = -8 

Observe that f '(-7) > 0 and f '(-9) < 0. Therefore, we have a relative min at x = -8. 

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

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8 0
4 years ago
A box with an open top has vertical sides, a square bottom, and a volume of 32 cubic meters. If the box has the least possible s
Umnica [9.8K]

Answer:

go ask photomath it is very helpful for math

3 0
3 years ago
Read 2 more answers
Larry runs a dog-walking service. He charges $5/h plus a flat fee of $6. One day, he earned $16. Determine which
frosja888 [35]

Answer:

5h+6=16

Step-by-step explanation:

He gets 6 dollars and for every hour he walks he gets 5 dollars so he must of walked dogs for 2 hours and plug it in you get your equation.

4 0
3 years ago
Read 2 more answers
F ( x ) = x − 3 x , g ( x ) = x + 3 , h ( x ) = 2 x + 1 , ( g ⋅ h ⋅ f ) ( x )
DiKsa [7]

Composing functions just means to feed the ouput of the inner one as the input for the outer one.

So, the following writings are equivalent:

(g\circ h \circ f)(x) = g(h(f(x)))

Using the second form, we can see that the first thing to do is to compute f(x), which is given:

f(x) = x-3

This means that we can update the fomula:

(g\circ h \circ f)(x) = g(h(f(x))) = g(h(x-3))

So, now we have to compute h(x-3). Given h(x)=2x+1, we know that h doubles the input and adds one. In this case, the input is x-3, so we have to double this and add one:

h(x-3) = 2(x-3)+1 = 2x-6+1 = 2x-5

So, we have

(g\circ h \circ f)(x) = g(h(f(x))) = g(2x-5)

Similarly, from g(x) = x+3, we understand that g just adds 3 to the input. In this case, the input is 2x-5, so we'll add 3 to this quantity:

g(2x-5) = (2x-5)+3 = 2x-2

So, we finally have

(g\circ h \circ f)(x) = g(h(f(x))) = 2x-2

8 0
3 years ago
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