Answer: $9
Step-by-step explanation:
all you have to do is divide it by 2 cuz there's 60 minutes in an hour
C) 12 pack is cheaper srry if i got it wrong
2(x)^2 - 2(x) - 12 = ?
2(x)^2 - 2(x) - 12
(x)^2 - 6 - x
Multiply ↪1 (-6) = -6
1 + -6 = -5 , right?
-3 + 2 = -1, right?
After we have pulled out the like terms we have to add/subtract! x(x) - 3
Search for the common denominator
2(x) - 3
You can add up 4 for your terms
x + 2 (x - 3)
Make sure you solve this↪ 2 = 0
x + 2 = ?
x + 2 = 0
We have found the first; x = -2
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Since, this one has a single variable, I'll make the step easier and quicker
Solve this part ↪ x-3 = 0
If we had the number 3 to your sides we would have found the outcome of the next x
So, the second x is 3
So, therefore your answer would have to be x =-2 ; x = 3 (most likely option C.)
The easiest way to tell whether lines are parallel, perpendicular, or neither is when they are written in slope-intercept form or y = mx + b. We will begin by putting both of our equations into this format.
The first equation,

is already in slope intercept form. The slope is 1/2 and the y-intercept is -1.
The second equation requires rearranging.

From this equation, we can see that the slope is -1/2 and the y-intercept is -3.
When lines are parallel, they have the same slope. This is not the case with these lines because one has slope of 1/2 and the other has slope of -1/2. Since these are not the same our lines are not parallel.
When lines are perpendicular, the slope of one is the negative reciprocal of the other. That is, if one had slope 2, the other would have slope -1/2. This also is not the case in this problem.
Thus, we conclude that the lines are neither parallel nor perpendicular.