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3 years ago

In circle Z, what is m∠2?

Mathematics

2 answers:

xz_007 [3.2K]3 years ago

8 0

Answer:

m < 2 is 140

Step-by-step explanation:

garik1379 [7]3 years ago

3 0

Answer:

In a circle, interior angles that are not inscribed or central can be found using the formula < = larger arc + smaller arc / 2. So, in order to find <2, the formula would be <2 = 147 + 133 / 2, so 140.

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benny had 266 dollars to spend on 9 books. After buying them he had 14 dollars. How much did each book cost?

Anastaziya [24]

Answer:

The books cost $28 dollars each.

Step-by-step explanation:

$266 - $14 = $252

then take $252 divided by 9 = $ 28

7 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

3 0

4 years ago

The last question I couldn't fit

Valentin [98]

Answer:

GOOD LUCK! NYAYAYAYAYAYA

7 0

3 years ago

Multiply: (5x2y – 3xy2)(3xy2 + 5x2y)<br> Please help I need to get this one right!

Aliun [14]

Answer:

(1): "*-5x2y" was replaced by "*(-5x2y)".

(2): "x2" was replaced by "x^2". 1 more similar replacement(s).

STEP

Equation at the end of step 1

(3x • (y2)) • (0 - (5x2 • y))

STEP

Equation at the end of step

3xy2 • -5x2y

STEP

Multiplying exponential expressions :

3.1 x1 multiplied by x2 = x(1 + 2) = x3

Multiplying exponential expressions :

3.2 y2 multiplied by y1 = y(2 + 1) = y3

I believe the answer is ( -3•5x3y3)

6 0

3 years ago

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Viefleur [7K]

Hello!

There are only six was to to role a number less than four. 1 and 1. 1 and 2. 2 and 1. 1 and 3. 2 and 2. 3 and 3 and 1.

The first number on the die could be 1, and the second die could have a probability of rolling the second number on it. Giving us a probability of 1/6.

We can subtract the calculated probability from rolling less than four from 1 to find the probability of rolling more than 5:

1 - 1/6 = 5/6

So, your answer should be D 5/6.

5 0

4 years ago

Read 2 more answers