6b6
——— (hope this helps)
ac2
Answer:
10x^2 y(2x + 3y)
Step-by-step explanation:
20x^3 y + 30x^2 y^2.
Factor 10x^2y out of 20x^3y.
10x^2 y (2x) + 30x^2 y^2
Factor 10x^2y out of 30x^2y^2.
10x^2 y (2x) + 10x^2 y (3y)
Factor 10x^2y out of 10x^2 y (2x) + 10x^2 y (3y).
10x^2 y(2x + 3y)
you factor out 10x^2y from both side which you will then get 10x^2 y (2x) + 10x^2 y (3y) than you factor out 10x^2y again and get 10x^2 y(2x + 3y) your third option
\left[x _{2}\right] = \left[ \frac{-1+i \,\sqrt{3}+2\,by+\left( -2\,i \right) \,\sqrt{3}\,by}{2^{\frac{2}{3}}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{24}+\left( \frac{-1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( 432\,by+\sqrt{\left( -6912+41472\,by+103680\,by^{2}+55296\,by^{3}\right) }\right) }}{\sqrt[3]{2}}\right][x2]=⎣⎢⎢⎢⎢⎡2323√(432by+√(−6912+41472by+103680by2+55296by3))−1+i√3+2by+(−2i)√3by+3√224−3√(432by+√(−6912+41472by+103680by2+55296by3))+(24−1i)√33√(432by+√(−6912+41472by+103680by2+55296by3))⎦⎥⎥⎥⎥⎤
totally answer.
Solution :
It is given that :
Number of students in a random sample majoring in communication or psychology at an university = 250
Total number of students majoring in psychology = 100
Number of students majoring in psychology those who are happy = 80
So number of students majoring in psychology those who are not happy = 20
Total number of students majoring in communication = 250 - 100 = 150
Number of students majoring in communication those who are happy = 115
So number of students majoring in psychology those who are not happy = 35
a). Probability of the students happy with their major choices are
= 0.78
b). Psychology major 
= 0.4
c). Probability of the students who are happy with the communication as the choice of major = 
= 0.46
d). Students unhappy with their choice of major given that the student is psychology major = 
= 0.018
