PLEASE HELP ASAP!! Please don’t just answer for points
2 answers:
You might be interested in
Answer: (0.8468, 0.8764)
Step-by-step explanation:
Formula to find the confidence interval for population proportion is given by :-
, where = sample proportion.
z* = Critical value
n= Sample size.
Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.
Given : Sample size = 3597
Number of students believe that they will find a job immediately after graduation= 3099
Then,
We know that , Critical value for 99% confidence interval = z*=2.576 (By z-table)
The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be
Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)
Answer:
A 56
C
Right triangle
No,No,No,Yes
Step-by-step explanation:
180-124=56
sin a=sideopposite/hypotnuse
8/17
cos a= side adjecent/hyptnuse
15/17
