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zvonat [6]
3 years ago
6

Use the Pythagorean Theorem to find the hypotenuse.

Mathematics
1 answer:
valkas [14]3 years ago
4 0
Is the hypotenuse not already shown? wouldn’t it just be 10…?

if your trying to find the value of the missing leg then that would 8.
10^2-6^2= b
100-36=64
square root of 64 is 8.


not sure if this was a trick question or just bad wording cause the longest leg- the hypotenuse is already shown in that image-10. otherwise if it was bad wording and means the missing leg, then that would be 8.

so based off the question it’s 10. it’s just weird how they said to use the pythagorean theorem when you don’t have to…
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A catering company provides packages for weddings and for showers. The cost per person for small groups
Tomtit [17]

Using the <em>normal distribution and the central limit theorem</em>, it is found that the probability the mean cost of the weddings is more than the mean cost of the showers is of 0.9665.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.
  • When two variables are subtracted, the mean is the subtraction of the means, while the standard error is the square root of the sum of the variances.

<h3>What is the mean and the standard error of the distribution of differences?</h3>

For each sample, they are given by:

\mu_W = 82.3, s_W = \frac{18.2}{\sqrt{9}} = 6.0667

\mu_S = 65, s_S = \frac{17.73}{\sqrt{6}} = 7.2382

For the distribution of differences, we have that:

\mu = \mu_W - \mu_S = 82.3 - 65 = 17.3

s = \sqrt{s_W^2 + s_S^2} = \sqrt{6.0667^2 + 7.2382^2} = 9.4444

The probability the mean cost of the weddings is more than the mean cost of the showers is P(X > 0), that is, <u>one subtracted by the p-value of Z when X = 0</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0 - 17.3}{9.4444}

Z = -1.83

Z = -1.83 has a p-value of 0.0335.

1 - 0.0335 = 0.9665.

More can be learned about the <em>normal distribution and the central limit theorem</em> at brainly.com/question/24663213

5 0
2 years ago
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ArbitrLikvidat [17]

Answer:  price of total notebooks = p(a+b+c) or pa+pb+pc= price of total notebooks

Step-by-step explanation:

you have to add all the number of notebooks or a b and c and then multiply it by the price of each notebook. there are multiple ways to do this but those are the ways I could think of.

 if a=2, b=3 and c=6 then you have to add 2+3+6 to equal 11 then multiply 11 by the price of each notebook, say p=$4.50  your equation would be 4.50*11 which is $49.50, and that would be the total of all the notebooks. these numbers metaphorical of course, but hope that puts it into perspective.

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Answer:

Answer is D.)

Step-by-step explanation:

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An urn contains 5 red balls and 2 green balls. Two balls are drawn one after the other. What is the probability that the second
AleksAgata [21]

Answer:

<em>The probability that the second ball is red is 71%</em>

Step-by-step explanation:

<u>Probabilities</u>

We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).

The first ball can be red (R) or green (G). The probability that it's red is computed by

\displaystyle P(R)=\frac{5}{7}

The probability is's green is computed by

\displaystyle P(G)=\frac{2}{7}

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

\displaystyle P(RR)=\frac{5}{7}\cdot \frac{4}{6}=\frac{10}{21}

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

\displaystyle P(GR)=\frac{2}{7}\cdot \frac{5}{6}=\frac{5}{21}

The total probability of the second ball being red is

\displaystyle P(XR)=\frac{10}{21}+\frac{5}{21}=\frac{5}{7}=0.71

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