Answer:1
Step-by-step explanation:
Answer: The answer is either letter A or letter C
home / math / slope calculator
Slope Calculator
By definition, the slope or gradient of a line describes its steepness, incline, or grade.
Where
m — slope
θ — angle of incline
If the 2 Points are Known
Result
Slope (m) =
ΔY
ΔX
=
-1
5
= -0.2
θ =
arctan( ΔY ) + 360°
ΔX
= 348.69006752598°
ΔX = 5 – -5 = 10
ΔY = -3 – -1 = -2
Distance (d) = √ΔX2 + ΔY2 = √104 = 10.198039027186
Equation of the line:
y = -0.2x – 2
or
y =
- 1 x
5
– -2
When x=0, y = -2
When y=0, x = -10
...............................................................................................................................................
home / math / slope calculator
Slope Calculator
By definition, the slope or gradient of a line describes its steepness, incline, or grade.
Where
m — slope
θ — angle of incline
If the 2 Points are Known
Result
Slope (m) =
ΔY
ΔX
=
5
-1
= -5
θ =
arctan( ΔY ) + 180°
ΔX
= 101.30993247402°
ΔX = -3 – -1 = -2
ΔY = 5 – -5 = 10
Distance (d) = √ΔX2 + ΔY2 = √104 = 10.198039027186
Equation of the line:
y = -5x – 10
When x=0, y = -10
When y=0, x = -2
...............................................................................................................................................
Input Data :
Point A
(
x
A
,
y
A
)
= (3, 2)
Point B
(
x
B
,
y
B
)
= (7, 10)
Objective :
Find the slope of a line that passes through points A and B.
Formula :
Slope
m
=
y
B
−
y
A
x
B
−
x
A
Solution:
Slope
m
=
10
−
2
7
−
3
=
8
4
m = 2
...............................................................................................................................................
Input Data :
Point A
(
x
A
,
y
A
)
= (3, 2)
Point B
(
x
B
,
y
B
)
= (7, 10)
Objective :
Find the slope of a line that passes through points A and B.
Formula :
Slope
m
=
y
B
−
y
A
x
B
−
x
A
Solution:
Slope
m
=
10
−
2
7
−
3
=
8
4
m = 2
Step-by-step explanation: This is the picture, I graphed it
Center: (0, 0)
Angle: 0 rad
Opacity: 1
Width: 10
Height: 6.8
Answer:
k=7
Step-by-step explanation:
4+k=11
subtract 4 from both sides to isolate k
k= 7
According to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.
We assume the brightness of a dim day to be x.
According to the developed scale, the brightness of an illuminated day will be 4 times that of a dim day.
Thus, the brightness of an illuminated day = 4*the brightness of a dim day = 4x.
According to the developed scale, the brightness of a radiant day will be 4 times that of an illuminated day.
Thus, the brightness of a radiant day = 4*the brightness of an illuminated day = 4*4x = 16x.
Now, the ratio of the brightness of a radiant day to the brightness of a dim day = 16x:x = 16x/x = 16:1.
Thus, according to the developed scale, a radiant day is <u>16 times</u> brighter than a dim day.
Learn more about the developed scale at
brainly.com/question/4970963
#SPJ1
The question provided is incomplete. The complete question is:
"Suppose you have developed a scale that indicates the brightness of sunlight. Each category in the table is 4 times brighter than the next lower category. For example, a day that is dazzling is 4 times brighter than a day that is radiant. How many times brighter is a radiant day than a dim day?
Dim=2
Illuminated=3
Radiant=4
Dazzling=5"