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Alborosie
3 years ago
6

Please help me, will mark brainliest for correct answers.....

Mathematics
1 answer:
Alexandra [31]3 years ago
8 0

Answer:

1. B) 5.7

2. A) 12

3. A) 11.4

4. A) 5.7

5. A) 16.2

6. A) 11.2

7. No, they do not form a right triangle

8. Yes, they do form a right triangle

Step-by-step explanation:

Extra tip: The hypotenuse has to be less than both sides added together, but cannot be more than either of the sides alone.

1.

16² + b² = 17²

256 + b² = 289

256 - 256 + b² = 289 - 256

b² = 33

√b² = √33

b = 5.74 or 5.7

2.

16² + b² = 20²

256 + b² = 400

256 - 256 + b² = 400 - 256

b² = 144

√b² = √144

b = 12

3.

7² + 9² = c²

49 + 81 = c²

130 = c²

√130 = √c²

11.40 or 11.4 = c

4.

7² + b² = 9²

49 + b² = 81

49 - 49 + b² = 81 - 49

b² = 32

√b² = √32

b = 5.65 or 5.7

5.

a² + 5² = 17²

a² + 25 = 289

a² + 25 - 25 = 289 - 25

a² = 264

√a² = √264

a = 16.24 or 16.2

6.

10² + b² = 15²

100 + b² = 225

100 - 100 + b² = 225 - 100

b² = 125

√b² = √125

b = 11.18 or 11.2

7.

15² + 8² = 16²

225 + 64 = 256

289 ≠ 256

8.

5² + 12² = 13²

25 + 144 = 169

169 = 169

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34kurt

Given:

\begin{gathered} a=2i+3 \\ b=i-1 \\ c=-3i+2 \end{gathered}

You know that:

a-b-c=(2i+3)-(i-1)-(-3i+2)

In order to solve the operation, you can follow these steps:

1. Distribute the negative signs. Remember the Sign Rules for Multiplication:

\begin{gathered} +\cdot+=+ \\ -\cdot-=+ \\ +\cdot-=- \\ -\cdot+=- \end{gathered}

Then:

=2i+3-i+1+3i-2

2. Combine the like terms (add the Real Parts and add the Imaginary Parts):

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The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

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(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

y= 3\cos(2(x + \pi/2)) - 2

The options are:

  1. y= 3\sin(2(x + \pi/4)) - 2
  2. y= -3\sin(2(x + \pi/4)) - 2
  3. y= 3\cos(2(x + \pi/4)) - 2
  4. y= -3\cos(2(x + \pi/2)) - 2

Checking all the options one by one:

  • Option 1: y= 3\sin(2(x + \pi/4)) - 2

y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

  • Option 2: y= -3\sin(2(x + \pi/4)) - 2

This option if would be true, then from option 1 and this option, we'd get:
-3\sin(2(x + \pi/4)) - 2= -3\sin(2(x + \pi/4)) - 2\\2(3\sin(2(x + \pi/4))) = 0\\\sin(2(x + \pi/4) = 0

which isn't true for all values of x.

Thus, this option is not same as the given function.

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The given function is y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2

This option's function simplifies as:

y= 3\cos(2(x + \pi/4)) - 2 = 3\cos(2x + \pi/2) -2 = -3\sin(2x) - 2

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The given function simplifies to:y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2

The given option simplifies to:

y= -3\cos(2(x + \pi/2)) - 2 = -3\cos(2x + \pi ) -2\\y = 3\cos(2x) -2

Thus, this function is not same as the given function.

Thus, the function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

Learn more about sine to cosine conversion here:

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