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Igoryamba
3 years ago
8

Byron’s income last year was $61,700. He made $48,000 at his plumbing job and had income from an apartment that he rented out. I

f Byron earned the same amount of rent each month for the entire year, approximately how much per month did he collect?
Mathematics
2 answers:
cricket20 [7]3 years ago
6 0
Total income minus income from plumbing gives us income from rent.  Divide that by 12 to give us the monthly income from rent.

61700-4800 = 13700

13700/12 = 1,141.67 a month in rent.
butalik [34]3 years ago
3 0

Answer:

B.  $1,140

Step-by-step explanation:

Edgenuity.

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nata0808 [166]

Answer:

B: 4

Step-by-step explanation:

A trapezoid have 4 sides.

Hope it helps you in your learning process

5 0
3 years ago
Read 2 more answers
If your finding the change in x, is it vertical or horizontal?
Basile [38]
Horizontal, by the way don listen to that just trying to get points
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3 years ago
If wxyz is a square with wz=27, find each measure
balandron [24]

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For a square all the sides are equal and measure 27

Step-by-step explanation:

8 0
3 years ago
Consider f and c below. f(x, y) = (3 + 4xy2)i + 4x2yj, c is the arc of the hyperbola y = 1/x from (1, 1) to 3, 1 3 (a) find a fu
irga5000 [103]
We want to find a scalar function f(x,y) such that \nabla f(x,y)=\mathbf f(x,y)=\dfrac{\partial f}{\partial x}\,\mathbf i+\dfrac{\partial f}{\partial y}\,\mathbf j.
So we need to have
\dfrac{\partial f}{\partial x}=3+4xy^2
Integrating both sides with respect to x gives
f(x,y)=3x+2x^2y^2+g(y)
Differentiating with respect to y gives
\dfrac{\partial f}{\partial y}=4x^2y+\dfrac{\mathrm dg}{\mathrm dy}=4x^2y\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C
So we find that
f(x,y)=3x+2x^2y^2+C
By the fundamental theorem of calculus, we then know the line integral depends only on the values of f(x,y) at the endpoints of the path. Therefore

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f\left(3,\frac13\right)-f(1,1)=11-5=6
4 0
4 years ago
Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of
Nata [24]
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
7 0
4 years ago
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