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3 years ago

15,60,240,... Find the 6th term .

Mathematics

1 answer:

ikadub [295]3 years ago

5 0

Answer:

61440

Step-by-step explanation:

15 x 4= 60

60 x 4= 240

240 x 4= 960

960 x 4= 3840

3840 x 4 = 15360

15360 x 4= 61440

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Can yall please help?

butalik [34]

Answer:

3000000000

Step-by-step explanation:

Dividing 9*10^7 by 3, we have 3*10^7

Same with 3*10^-2 so we have

(3*10^7)/(1/100) which is equal to 3*10^7*100 which is equal to 3000000000

Please give me Brainliest if im correct

3 0

3 years ago

A customer deposits $500 in an account that pays 4% annual interest. What is the balance after 3 years if the interest is compou

lana [24]

A(t) = P(1+(r/n))^(nt)

A(3) = 500(1+0.04/1))^(1*3)

A(3) = 500(1.04)^3

A(3) = $562.43

6 0

3 years ago

Read 2 more answers

Solve for r.<br><br> 3r − 2r =

alexandr402 [8]

The answer if i’m not wrong would be r 3-2 equals 1 which is r.

3 0

3 years ago

Find the laplace transform of f(t) = cosh kt = (e kt + e −kt)/2

iren2701 [21]

Hello there, hope I can help!

I assume you mean $L\left\{\frac{ekt+e-kt}{2}\right\}$
With that, let's begin

$\frac{ekt+e-kt}{2}=\frac{ekt}{2}+\frac{e}{2}-\frac{kt}{2} \ \textgreater \ L\left\{\frac{ekt}{2}-\frac{kt}{2}+\frac{e}{2}\right\}$

$\mathrm{Use\:the\:linearity\:property\:of\:Laplace\:Transform}$
$\mathrm{For\:functions\:}f\left(t\right),\:g\left(t\right)\mathrm{\:and\:constants\:}a,\:b$
$L\left\{a\cdot f\left(t\right)+b\cdot g\left(t\right)\right\}=a\cdot L\left\{f\left(t\right)\right\}+b\cdot L\left\{g\left(t\right)\right\}$
$\frac{ek}{2}L\left\{t\right\}+L\left\{\frac{e}{2}\right\}-\frac{k}{2}L\left\{t\right\}$

$L\left\{t\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{t\right\}=\frac{1}{s^2} \ \textgreater \ L\left\{t\right\}=\frac{1}{s^2}$

$L\left\{\frac{e}{2}\right\} \ \textgreater \ \mathrm{Use\:Laplace\:Transform\:table}: \:L\left\{a\right\}=\frac{a}{s} \ \textgreater \ L\left\{\frac{e}{2}\right\}=\frac{\frac{e}{2}}{s} \ \textgreater \ \frac{e}{2s}$

$\frac{ek}{2}\cdot \frac{1}{s^2}+\frac{e}{2s}-\frac{k}{2}\cdot \frac{1}{s^2}$

$\frac{ek}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{ek\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{ek}{2s^2}$

$\frac{k}{2}\cdot \frac{1}{s^2} \ \textgreater \ \mathrm{Multiply\:fractions}: \frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d} \ \textgreater \ \frac{k\cdot \:1}{2s^2} \ \textgreater \ \mathrm{Apply\:rule}\:1\cdot \:a=a$
$\frac{k}{2s^2}$

$\frac{ek}{2s^2}+\frac{e}{2s}-\frac{k}{2s^2}$

Hope this helps!

3 0

4 years ago

The expresssion is also equivalent to the cost of the item? c-0.25 c which expression is also equivalent to the cost of the item

MArishka [77]

Answer:

0.75c

Step-by-step explanation:

If we have an expression as:

a*x + b*x

We can see that both terms in the expression, a*x and b*x have an x, so we can call the x a common factor and we can write an equivalent expression as:

a*x + b*x = (a + b)*x

If we replace, for example, a by 2, b by 3 and x by 4, we can test the expression as:

2*4 + 3*4 = (2 + 3)*4

8 + 12 = (5)*4

20 = 20

Therefore, if we have the following expression:

c - 0.25*c

The expression that is equivalent is 0.75c and it is calculated as:

c - 0.25*c = (1 - 0.25)*c

c - 0.25*c = 0.75*c

8 0

3 years ago