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3 years ago

What is the common difference and ninth term for the following sequence: 3,5/2,2,3/2,1

Mathematics

1 answer:

Stells [14]3 years ago

3 0

Answer:

Common Difference: $-\frac{1}{2}$

The ninth term: -1

Step-by-step explanation:

The sequence can be written like this,

3, 2.5, 2, 1.5, 1, ....

Here the common difference is clearly -0.5 or $-\frac{1}{2}$ , and we can conclude that $n^{th}$ number is $3 - 0.5(n-1)$ . So the 9th term is,

$3 - 0.5(9 - 1)\\= -1$

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In △ABC, m∠A=27°, c=14, and m∠B=25°. Find a to the nearest tenth.

Alenkinab [10]

Answer:

8.1

Step-by-step explanation:

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3 years ago

(I NEED THIS ANSWERED SUPER SUPER FAST PLEASE IT'S IMPORTANT!!!!!!)<br><br> 6 7/8c =__ fl oz

Olegator [25]

1 cup = 8 fluid ounces.
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3 years ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0

3 years ago

Read 2 more answers

How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?

dem82 [27]

How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?

Answer: the third option (12 zeros..).

Use ^ to denote an exponent..

f(x) = 3x^12 - 17x^8 + 11x^4 - 6x + 23..

We know from that fact that the number of zeros (real or complex) in a polynomial is the same as the degree of the polynomial..

The degree is the greatest/highest power of the terms, which in this case is 12 (since 12 is the greatest exponent..)..

The degree is 12, thus it means there are 12 zero's..

Answer: the third option (12 zero's )...

3 0

3 years ago

Eric conducted a survey of the cars in four parking lots and wrote the following observations:

vredina [299]

Answer:

1- 42%

2- 47%

3- 40%

4- 62%

parking lot 4 had the greatest percentage of blue cars

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers