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sasho [114]
3 years ago
5

What is the common difference and ninth term for the following sequence: 3,5/2,2,3/2,1

Mathematics
1 answer:
Stells [14]3 years ago
3 0

Answer:

Common Difference: -\frac{1}{2}

The ninth term: -1

Step-by-step explanation:

The sequence can be written like this,

3, 2.5, 2, 1.5, 1, ....

Here the common difference is clearly -0.5 or -\frac{1}{2}, and we can conclude that n^{th} number is 3 - 0.5(n-1). So the 9th term is,

3 - 0.5(9 - 1)\\= -1

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Step-by-step explanation:

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3 years ago
The sum of a two digit number and the number obtained by interchanging the digits is 132. If the two digits differ by 2, find th
damaskus [11]

Answer:

A two-digit number can be written as:

a*10 + b*1

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We know that:

"The sum of a two-digit number and the number obtained by interchanging the digits is 132."

then:

a*10 + b*1 + (b*10 + a*1) = 132

And we also know that the digits differ by 2.

then:

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So let's solve this:

We start with the equation:

a*10 + b*1 + (b*10 + a*1) = 132

(a*10 + a) + (b*10 + b) = 132

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Then:

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And remember that:

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Then if we select the first one, we get:

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The number is 75.

And if we selected:

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Both are valid solutions because we are changing the order of the digits, so is the same:

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