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sasho [114]
3 years ago
5

What is the common difference and ninth term for the following sequence: 3,5/2,2,3/2,1

Mathematics
1 answer:
Stells [14]3 years ago
3 0

Answer:

Common Difference: -\frac{1}{2}

The ninth term: -1

Step-by-step explanation:

The sequence can be written like this,

3, 2.5, 2, 1.5, 1, ....

Here the common difference is clearly -0.5 or -\frac{1}{2}, and we can conclude that n^{th} number is 3 - 0.5(n-1). So the 9th term is,

3 - 0.5(9 - 1)\\= -1

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Answer:

8.1

Step-by-step explanation:

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3 years ago
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Olegator [25]
1 cup = 8 fluid ounces.
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3 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have?
dem82 [27]
How many zeros does the function f(x) = 3x12 − 17x8 + 11x4 − 6x + 23 have? 

Answer: the third option (12 zeros..). 

Use ^ to denote an exponent.. 

f(x) = 3x^12 - 17x^8 + 11x^4 - 6x + 23.. 


We know from that fact that the number of zeros (real or complex) in a polynomial is the same as the degree of the polynomial.. 

The degree is the greatest/highest power of the terms, which in this case is 12 (since 12 is the greatest exponent..).. 

The degree is 12, thus it means there are 12 zero's.. 


Answer: the third option (12 zero's )...
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Answer:

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Step-by-step explanation:

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3 years ago
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