Answer:
x = 20
Step-by-step explanation:
Since the 2 angles are directly across from each other they share the same agle meaning u can make them equal to each other 3x+50=6x-10
So the rule of solving this type of equation is to get the variable on one side of the equation but u have to follow the zero property 3x-3x+50=6x-3x-10
So then u get 50 = 3x-10 so use the same rule to get the 10 to the other side 50+10= 3x-10+10
Then you get 60 = 3x then just use the division property of equality
60/3=3x/3 and x = 20
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Permutations are all possible variations, in which a set of numbers or characters can be ordered. <span>The number of permutations on a set of </span><span> n elements is given by </span><span> n!. </span>In our case we have 9 digits, which means 9 elements.
There are 9!=9*8*7*6*5*4*3*2*1=362880 possible variations, or 362880 possible identification numbers.
I think that there is 47 chocolate chips in total
Profit = Income - cost
Profit = 10s - (28 + 3s) = 10s - 28 -3s = 7s - 28.
Profit = 0
0 = 7s - 28
7s = 28
7s = 28/7
s = 4. This is the breakeven point.
Carlota must sell more than 4 shirts to make a profit
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
