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3 years ago

Two Submarines starting from the same point cruise for two hours, one

Mathematics

1 answer:

Aleksandr [31]3 years ago

5 0

Answer:

2 hour

Step-by-step explanation:

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Pls answer this!!!!!!!!!!!!

Artyom0805 [142]

The answer to the question is 90

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2 years ago

Read 2 more answers

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago

What problem types can be solved using law of sines?

aev [14]

Let's take a triangle ABC, with a, b, and c the sides length, he law of sine is:

a/sin A =b/sin B = c/sin C
If we know the value of 2 angles and one side or the value of 2 sides and one angle, we can calculate all the elements of the triangle

6 0

2 years ago

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HELP THIS IS DUE IN 15 MINUTES I DONT KNOW HOW TO SOLVE IT!!!

NARA [144]

Answer:

(x,y)=(-10, -30)

Step-by-step explanation:

x/4 -y/12 = 0

--> x/4 = y/12

substitute into the first eq.

x/4 + y/12 = -5

y/12 + y/12 = -5

2y/12 = -5

y= (-5) * 12/2 = -30

solve for x, x/4 = (-30)/12

x=4* (-30)/12 = -10

8 0

2 years ago

Solve for g: C = 1/2gk

sweet-ann [11.9K]

Answer:

G = $\frac{C(2)}{k}$

Step-by-step explanation:

C = 1/2gk

First you want to multiple both sides by 2 to get rid of that fraction and you get

C (2) = gk then you divide both sides by k to isolate the g and your left with

G= $\frac{C(2)}{k}$

Hope this helps

5 0

2 years ago