3 years ago

(PLEASE IM DESPERATE) 3. A toy catapult launched a ball. The height of the ball could be modelled by

Mathematics

1 answer:

Elena-2011 [213]3 years ago

8 0

Answer:

I think it could be modelled by the function I'm not 100 percent sure but i hope it helps

Step-by-step explanation:

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PLEASE HELP!!!!!!!<br> (do not answer if you do not know, so the points go to people who do know.)

zheka24 [161]

Answer:

1a = 8 cu. in.

1b = 48 cu. yd.

1c = 15 cu. ft.

2a. 36 cu. yd.

2b = 126 cu. ft.

2c = 90 cu. ft.

3a = 112 cu. in.

3b = 60 cu. yd.

3c = 189 cu. ft.

Step-by-step explanation:

8 0

3 years ago

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Which property of multiplication is used to rename 5/6 to 10/12?

yan [13]

Fraction is used to rename 5/6

7 0

3 years ago

What ratios are equivalent to 4:3

Brums [2.3K]

Answer:

here are a few that are equivalent

8:6

28:21

48:36

68:51

4 0

3 years ago

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Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.

Levart [38]

Answer:

The standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Step-by-step explanation:

We know that:

$4p\left(y-k\right)=\left(x-h\right)^2$ is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

$x^2\:+\:10x\:+\:6y\:=\:47$

Rewriting the equation in the standard form

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by $x^2\:+\:10x\:+\:6y\:=\:47$ is:

$4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2$

where

vertex (h, k) = (-5, 12)

7 0

3 years ago

What is the product 3x^5(2x^2 +4x+1)

juin [17]

Answer:

6x^7 + 12x^6 + 3x^5

Step-by-step explanation:

Simplify the expression.

5 0

3 years ago

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