Answer:
See below.
Step-by-step explanation:
Plot some points:
y = 4^x
When x = 0 y = 4^0 = 1 so the graph passes through (0,1).
x = 1, y = 4^1 = 4 so it passes through (1,4).
You can plot a few more points for x = 2 and x = 3 . You'll see that the graph rises at a fast rate for positive values of x.
When x = -1 , y = 4^-1 = 1/4
x = -2 , y = 1/16
x = -3, y = 1/64
Thus, for negative values of x, the values of y rise slowly from close to y = 0 to meet the y axis at y = 1. When x approaches negative infinity y is very close to 0 but never is 0.
The equation of the line fully simplified in slope intercept form is y = 10/3x - 8
<h3>What are linear equations?</h3>
Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient
<h3>How to determine the equation?</h3>
The points are given as:
(0, - 8) and (3, 2).
Calculate the slope of the line using
m = (y2 - y1)/(x2 - x1)
This gives
m = (2 + 8)/(3 - 0)
Evaluate
m = 10/3
The equation is then calculated as:
y = m(x - x1) + y1
This gives
y = 10/3(x -0) - 8
Evaluate
y = 10/3x - 8
Hence, the equation of the line fully simplified in slope intercept form is y = 10/3x - 8
Read more about linear equations at:
brainly.com/question/14323743
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<u>Complete question</u>
Write the equation fully simplified slope intercept form of a line that passes though the points (0, - 8) and (3, 2).
Answer:
x = 3 or x = 2 or x = -6
Step-by-step explanation:
Solve for x:
(x - 3) (x^2 + 4 x - 12) = 0
Split into two equations:
x - 3 = 0 or x^2 + 4 x - 12 = 0
Add 3 to both sides:
x = 3 or x^2 + 4 x - 12 = 0
The left hand side factors into a product with two terms:
x = 3 or (x - 2) (x + 6) = 0
Split into two equations:
x = 3 or x - 2 = 0 or x + 6 = 0
Add 2 to both sides:
x = 3 or x = 2 or x + 6 = 0
Subtract 6 from both sides:
Answer: x = 3 or x = 2 or x = -6
Answer:
-2
Step-by-step explanation:
(y-2)=-(12/4)
y-2= -4
y= -4+2
y = -2
Remember the quadratic formula determinant?
If b^2 -4ac < 0, a complex root exists.
So for this problem, m^2 - 4q is the determinant, and if less than 0, is complex.
So a=-m/2 and b=(1/2)SQRT(m^2 - 4q)