A quadrilateral has angles that measure 74°, 93°, and 117°.
1 answer:
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Answer:
And the circumference is given by this formula:
And replacing the value fo r we got:
And then the final answer would be 62.8 units for the circumference.
Step-by-step explanation:
For this case we know that the area for a circle is given by:
And we know that
We can find the radius from the previous formula like this:
And the circumference is given by this formula:
And replacing the value fo r we got:
And then the final answer would be 62.8 units for the circumference.
The answer is ![f^{-1}(x) = \sqrt[3]{ \frac{x-3}{6}}](https://tex.z-dn.net/?f=%20f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7Bx-3%7D%7B6%7D%7D)
Our function is f(x) = 6x³ + 3. We need to find f⁻¹(x)
Step 1: Substitute y for f(x):
y = 6x³ + 3
Step 2: Switch x and y because every (x, y) has its partner (y, x):
x = 6y³ + 3
Step 3: Solve for y:
![6y^{3} =x-3 \\ y^{3}= \frac{x-3}{6} \\ y = \sqrt[3]{ \frac{x-3}{6}}](https://tex.z-dn.net/?f=6y%5E%7B3%7D%20%3Dx-3%20%5C%5C%20%0Ay%5E%7B3%7D%3D%20%5Cfrac%7Bx-3%7D%7B6%7D%20%5C%5C%20%0Ay%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7Bx-3%7D%7B6%7D%7D%20%20)
![f^{-1}(x) = \sqrt[3]{ \frac{x-3}{6}}](https://tex.z-dn.net/?f=%20f%5E%7B-1%7D%28x%29%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7Bx-3%7D%7B6%7D%7D)
Our function is f(x) = 6x³ + 3. We need to find f⁻¹(x)
Step 1: Substitute y for f(x):
y = 6x³ + 3
Step 2: Switch x and y because every (x, y) has its partner (y, x):
x = 6y³ + 3
Step 3: Solve for y: