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lesya [120]
3 years ago
12

A quadrilateral has angles that measure 74°, 93°, and 117°.

Mathematics
1 answer:
Tamiku [17]3 years ago
4 0
We know the sum of all the angles in a quadilateral is equal to 360. so,
it would be: 360 - (74+93+117)

 = 360 - 284
 = 76 degrees

So, Your final answer is 76 degrees.

Hope this helps!
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What is the Lena equation in the slope intercept form( 2x - y = 7)
Archy [21]

Answer


Step-by-step explanation:x=7+y=2


3 0
3 years ago
How can you move just one number to a different
alexandr1967 [171]

Answer:

Remove 9 from triangle B to A

Step-by-step explanation:

Given

Three Triangles

A: 1,2,3

B: 7,8,9

C: 4,5,6

Required

Make their sum equal

First, we need to calculate the sum in each triangles;

A = 1 + 2 + 3

A = 6

B = 7 + 8 + 9

B = 24

C = 4 + 5 + 6

C = 15

Remove 9 from triangle B to A

A = 6 + 9

A = 15

B = 24 - 9

B = 15

At this point, we have:

A = 15     B = 15     C = 15

<em>Hence, the solution is to remove 9 from B to A</em>

6 0
3 years ago
7x + 2y = 7<br> -14x + 2y = -11<br> Solve by substitution
kvasek [131]

Answer:

x = 6/7, y = 1/2

Step-by-step explanation:

7x + 2y = 7

-14x + 2y = -11

1) 7x + 2y = 7

2y = 7 - 7x

2) -14x + 2y = -11

-14x + 7 - 7x = -11

- 21x = -11-7

- 21x = - 18

x = 18/21 = 6/7

3) 2y = 7 - 7x = 7 - 7*(6/7) = 7 - 6 = 1

2y = 1

y = 1/2

7 0
3 years ago
Val is going to plant d vegetable seeds in one garden and 3d + 8 vegetable seeds in another. How many seeds is Val going to​ pla
konstantin123 [22]
D = 11 seeds planted
8 0
3 years ago
Read 2 more answers
An acute triangle has sides measuring 10 cm and 16 cm. The length of the third side is unknown.
saveliy_v [14]

Answer: Choice B

12.5 < x < 18.9

================================================

Explanation:

We have a triangle with these side lengths:

  • a = 10
  • b = 16
  • c = x = unknown

Let's assume that b = 16 is the largest side of this triangle.

By the converse of the pythagorean theorem, we need b^2 < a^2+c^2 to be true in order for an acute triangle to happen.

So,

b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5

Now let's consider the possibility that the missing side x is actually the longest side.

Using the same theorem as before, we would say,

c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\

We found that x > 12.5 and x < 18.9

This is the same as saying 12.5 < x and x < 18.9

Put together, they form the approximate answer of 12.5 < x < 18.9

6 0
2 years ago
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