<h3>What is the greatest common factor of 15x³y² and 20x⁴y⁴? </h3>
<em>First we have to find the factors of 15x³y²</em>
<em>15x³y² = 3 * 5x³y² </em>
<em>Then we have to find the factors of 20x⁴y⁴</em>
<em>20x⁴y⁴ = 2²x¹y² * 5x³y²</em>
<em>Now we have to find the common factors to both numbers.</em>
<em>The common factors are </em><em>5x³y²</em>
Answer : GCF = (15x³y²,20x⁴y⁴) = 5x³y²
Hope this helps!
-4.5 or -4.3 i’m not really sure i’m just estimating
The answer is the 989 is the answer
Answer:
If they are travelling in opposite directions, their total distance is the 135. So add their distances together to get 135
x=Quinn's speed
x+5 = James' speed
they each travel for 5 hours
speed x time = distance
x(5) + (x+5)(5) = 135
Quinn's distance + James' distance = total distance
5x+5x+25=135
10x = 110
x = 11
Quinn travels at 11 mph and James travels at 16 mph
Quinn travels 55 miles (5x11)
and James travels 80 miles (16 x 5)
80 + 55=135
I think the distance is 8 1/8 feet
