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mixas84 [53]
3 years ago
15

Steve must pay 28% of his salary in federal income tax. If his salary this year is $168,000, how much is his federal income tax?

Mathematics
1 answer:
Leokris [45]3 years ago
3 0

Answer:

hi

Step-by-sp explanation:

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Solve the two-step equation.− 23 x – 214 = 274x =
Pachacha [2.7K]
U have to divide the numbers with the variables and then you'll get knocked down to the division and u have your answers and it is possible to have 1 or 2 answers v

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The drawing of a building shown below has a scale of 1 inch to 30 feet. What is the acual height in feet of the building?
mylen [45]
Multiply the amount of inches it is by 30 and you will know what the size is in feet.

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4 years ago
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Which expression is equivalent to 4 over 9 (2n - 3)
AlexFokin [52]

Answer:

The result for this equation is \frac{8}{9}n - \frac{4}{3} .

Step-by-step explanation:

-Solve:

\frac{4}{9} (2n-3)

-Multiply 2n and -3 by \frac{4}{9} :

\frac{8}{9} + \frac{-12}{9}

-Reduce \frac{-12}{9} to the lowest term by extracting and canceling out 3:

\frac{8}{9}n - \frac{4}{3}

-So, the result is \frac{8}{9}n - \frac{4}{3} .

3 0
3 years ago
Y varies directly with x, and y = 5 when x = 4. What is the value of x when y = 8?
Tomtit [17]
As y varies directly with x, there is a proportionality constant. As x increases by that certain constant, y also increases. We equate:
y = kx
where k = proportionality constant.
Given the condition, y = 5 when x = 4, then we solve for k:
5 = k(4)
k = 5/4 or 1.25
When y = 8, then
8 = (5/4)(x)
x = 8/(5/4) = (8)(4/5) = 32/5 or 6.4 (ANSWER)
7 0
4 years ago
1. A farmer divided a field into 1-foot by 1-foot sections and tested soil samples from 32 randomly selected sections in the fie
Ad libitum [116K]
Part A

Answers:
Mean = 5.7
Standard Deviation = 0.046

-----------------------

The mean is given to us, which was 5.7, so there's no need to do any work there.

To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046

================================================

Part B

The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949

The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67

================================================

Part C

Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.

-----------------------

At 95% confidence, the critical value is z = 1.96 approximately

ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657

L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99

U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
5 0
3 years ago
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