Exponential growth of the form:
F=Ar^t
F=100(1.22)^t
F(5)=100(1.22)^5
F(5)=270.27
F(5)=270 to the nearest frog...
....
1.22=r^12
r=1.22^(1/12)
F=100(1.22^(1/12)^t)
F=100(1.22^(t/12)) now it will produce monthly populations...
Say we did the same as before but instead of 5 years you have 60 months...
F(60)=100(1.22^(60/12))
F(60)=270 to the nearest frog... :P
√65Explanation:(−5,1)=x1,y1(3,0)=x2,y2The distance is calculated using formula:'Distance =√(x2−x1)2+(y2−y1)2=√(3−(−5))2+(0−1)2=√(3+5)2+(−1)2=√(8)2+(−1)2=√(64+1)Distance =√65
Answer:
it decreases by 31.50 ur welcome
Step-by-step explanation:
Answer:
100% increase
Step-by-step explanation:
well first let's find out how much a 100% increase would be. 6,540 + 6,540(when trying to find a 100% change add the number to itself) = 13,080. that gets the answer, so there is no need to continue.
Answer:
Yes Jeff is the correct answer
Step-by-step explanation:
