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2 years ago

8

A box is filled with five green card six green card and three blue cars. A card is chosen at random from the box. What is the Pr

obability that it is a green or blue card

1 answer:

VladimirAG [237]2 years ago

3 0

Answer:

so there is 14 cards in total so out of those 14 14 cards are either blue or green so 100%

Hope This Helps!!!

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The product of three positive integers is 300. If one of them is 5, what is the

Elan Coil [88]

Answer and Step-by-step explanation:

So, we are told that 3 positive integers multiply to be 300, and that one of the integers is 5.

First, we divide 300 by 5.

The result is 60.

Now, we take different (reasonable) numbers that add to 16:

10 and 6

12 and 4

We can see here that 10 and 6 are the integers because they add up to 16 and multiplies to 60.

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3 years ago

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

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Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

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2 years ago

Can someone help me with my homework please?

grigory [225]

Multiplying x^2 by 5 stretches the graph vertically by a factor of 5. Try graphing both x^2 and 5x^2 and see for yourself that this is correct.

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3 years ago

For the inverse variation equation xy = k, what is the value of x when y = 4 and k = 7? 3 28

Oliga [24]

Answer:

The value of x is $\frac{7}{4}$ .

Step-by-step explanation:

It is given that the inverse variation equation is

$xy=k$ ..... (1)

The value of y is 4 and the value of k is 7.

Substitute y=4 and k=7 in equation (1).

$x\times 4=7$

Divide both sides by 4.

$\frac{x\times 4}{4}=\frac{7}{4}$

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Therefore the value of x is $\frac{7}{4}$ .

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The answer would be 7 passes

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