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MatroZZZ [7]
2 years ago
15

Manuel ate 1/3 of the cracker on a plate. His brother ate 1/4 of the cracker. their were 5 crackers left on the plate. How many

cracker were there to begin with?
Mathematics
2 answers:
Lynna [10]2 years ago
6 0
5 and 7/12 of a cracker
Marina86 [1]2 years ago
4 0
1/3 + 1/4 = 4/12 + 3/12 = 7/12
7/12 =  both brothers ate 7 crackers out of 12 crackers

<span>there were 5 crackers left on the plate means 5/12 crackers left on the plate

answer: 12 crackers at the begining


</span>
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Suppose a parabola has an axis of symmetry at x=-5, a maximum height of 9, and passes through the point (-7,1). Write the equati
Nutka1998 [239]

the parabola has maximum at 9, meaning is a vertical parabola and it opens downwards.

it has a symmetry at x = -5, namely its vertex's x-coordinate is -5.

check the picture below.

so then, we can pretty much tell its vertex is at (-5 , 9), and we also know it passes through (-7, 1)


\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{using this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=9 \end{cases}\implies y=a[x-(-5)]^2+9\implies y=a(x+5)^2+9


\bf \textit{we also know that } \begin{cases} x=-7\\ y=1 \end{cases}\implies 1=a(-7+5)^2+9 \\\\\\ -8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y=-2(x+5)^2+9~\hfill

7 0
3 years ago
Find the y-intercept of the following equation. Simplify your answer.
o-na [289]

Answer:

<h2><em><u>Brainliest!</u></em></h2>

Step-by-step explanation:

the equation is y=mx+b

the b part is the y-intercept

so in your equation... the y=intercept would be 7/6

7 0
2 years ago
Simon has a certain length of fencing to enclose a rectangular area. The function
TiliK225 [7]

Answer:

336

Step-by-step explanation:

6 0
2 years ago
What is the value of x in the figure? Enter your answer in the box.<br> 145°<br> (2x + 15)°<br> x=
Nikolay [14]

Answer:

Answer: x=65

Step-by-step explanation:

Since they're vertical angles both sides are equal to 145 degrees

So, 145-15= 130 to get rid of the constant

Then, 130/2=65

To check you work add up all of your solutions to get 145

2*65=130 & 130+15=145

Therefore, x=65

8 0
2 years ago
Read 2 more answers
If a and B are the zeros of the quadratic polynomial f(x) = x2- 5x + 4 find the value of 1/a+1/b-2ab
bearhunter [10]

Answer:

<h2>-27/4</h2>

Step-by-step explanation:

Given the quadratic polynomial given as g(x) = x²- 5x + 4, the zeros of the quadratic polynomial occurs at g(x) = 0 such that x²- 5x + 4 = 0.

Factorizing the resulting equation to get the roots

x²- 5x + 4 = 0

(x²- x)-(4 x + 4) = 0

x(x-1)-4(x-1) = 0

(x-1)(x-4) = 0

x-1 = 0 and x-4 = 0

x = 1 and x = 4

Since a and b are known to be the root then we can say a = 1 and b =4

Substituting the given values into the equation  1/a+1/b-2 ab , we will have;

= 1/1 + 1/4 - 2*1*4

= 1 + 1/4 - 8

= 5/4 - 8

Find the Lowest common multiple

= (5-32)/4

= -27/4

<em>Hence the required value is -27/4</em>

5 0
3 years ago
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