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schepotkina [342]
4 years ago
13

Which statements are true about the ordered pair (-3, 1) and the system of

Mathematics
1 answer:
never [62]4 years ago
4 0

The ordered pair (-3, 1) is not a solution to system because it makes at least one of the equations false

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

x - 4y = 6 ------- eqn 1

3x + y = -8 ------------ eqn 2

Given ordered pair is (-3, 1)

We have to check if the options are true

<em><u>Let us substitute (x, y) = (-3, 1) in eqn 1</u></em>

-3 - 4(1) = 6\\\\-3 - 4 = 6\\\\-7\neq 6

Thus the given ordered pair (-3, 1) did not satisfy the first equation

<em><u>Substitute (x, y) = (-3, 1) in eqn 2</u></em>

3(-3) + 1 = -8\\\\-9 + 1 = -8\\\\-8 = -8

Thus the given ordered pair (-3, 1) satisfied the second equation

But for a ordered pair to be a solution to system of equations, it must satisfy both the equations

Thus the ordered pair (-3, 1) is not a solution to system because it makes at least one of the equations false

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Ms.Wright opens a savings account with a deposit of $800. The bank will pay her 3% interest per year A.) how much interest will
Norma-Jean [14]

A) Ms.Wright receive $12 as interest at the end of 1/2 year.

B)  Ms.Wright receive $24 as interest at the end of 1 year.

Step-by-step explanation:

The sum deposited in the bank = Principle  = $800

The rate of simple interest  = 3%

The time = 6 months  = (6/12) years   =  0.5 years

\textrm{SIMPLE INTEREST} =  \frac{P \times R \times t}{100} \\\implies SI  = \frac{800 \times 3 \times 0.5}{100}  = 12

So, here simple interest = $12.

So Ms.Wright receive $12 as interest at the end of 1/2 year.

B) Now here Time  = 1 year

so, Simple interest   = \frac{800 \times 3 \times1 }{100}  = 24

So Ms.Wright receive $24 as interest at the end of 1 year.

3 0
3 years ago
A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 0.8 ft/s,
shusha [124]

Answer:

-0.133 radians/s is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall.

Step-by-step explanation:

Let

x= distance between the wall and ladder

Ф = angle between the ladder and ground

The rate of change is: dx/dt = 0.8 ft/s

We need to find dФ/dt when x = 8 ft/s

From the triangle in the figure we see that:

cos Ф = x/10

=> x = 10 cosФ

Now, the rate of change will be

d(x)/dt = d/dt (10cosФ)

dx/dt = -10 sin Ф dФ/dt

dx/dt = 0.8 (given)

to find dФ/dt

we need to find sin Ф when x = 8

By Pythagoras theorem

(hypotenuse)^2 = (Perpendicular)^2+(base)^2

(10)^2 = (8)^2+ (Perpendicular)^2

100 = 64 +  (Perpendicular)^2

=>  (Perpendicular)^2 = 100-64

(Perpendicular)^2 = 36

Perpendicular = 6

sin Ф = Perpendicular/hypotenuse

sin Ф = 6/10 = 3/5

Putting values in:

dx/dt = -10 sin Ф dФ/dt

0.8 = -10(3/5) dФ/dt

0.8 = -6 dФ/dt

=> dФ/dt = 0.8 / -6

dФ/dt = - 0.133 radians/s

So, -0.133 radians/s is the angle between the ladder and the ground changing when the bottom of the ladder is 8 ft from the wall.

3 0
3 years ago
F(x)=(x+1)(x+3)(x−4 the standard form of F(x)
olga55 [171]

Answer:

f(x)=x^3-13x-12

Step-by-step explanation:

4 0
4 years ago
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Read 2 more answers
-25/J = 5<br> 16 + s = -90<br> 13 + t = 51<br> r/10 = (-6)<br> a + -12 =45
alexandr1967 [171]

we conclude that the solution for the given algebraic expressions are:

  • J = -5
  • s = -106
  • t = 38
  • r = -60
  • a = 57

<h3>How to solve these algebraic expressions?</h3>

Here we have some simple algebraic expressions:

The first one is:

-25/J = 5

We want to solve this for J.

Remember that we can perform the same operation in both sides of the equation, then we cans tart by multiplying both sides by J.

(-25/J)*J = 5*J

-25 = 5*J

Now we can divide both sides by 5, so we isolate J:

(-25)/5 = (5*J)/5

-5 = J

We conclude that the solution is J = -5.

Now, similarly for the other equations we have that:

16 + s = -90

Here we subtract 16 in both sides:

s = -90 - 16 = -106

13 + t = 51

Here we subtract 13 in both sides:

t = 51 - 13 = 38

r/10 = (-6)

Here we multiply both sides by 10:

r = (-6)*10 = -60

a + (-12) = 45

Here we add 12 in both sides:

a = 45 + 12 = 57

Then we conclude that the solution for the given algebraic expressions are:

  • J = -5
  • s = -106
  • t = 38
  • r = -60
  • a = 57

If you want to learn more about algebraic expressions:

brainly.com/question/4344214

#SPJ1

6 0
2 years ago
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