Find the minimum value of the parabola<br> y = x2 + x .

A one-year membership to metro gym cost $460.There is a fee of $40 when you join and the rest is paid monthly.Write an equation

Andrews [41]

40 when you join and the rest is paid monthly.Write an equation to represent the situation that can help members find how much they pay per month

5 0

2 years ago

If m <br> Answer choices are -<br><br> Which property is shown<br><br> Reflexive<br> Substitution <br> Symmetric<br> Transitive

ss7ja [257]

Answer: symmetric or reflexive

Step-by-step explanation:

I'm not forsure but I believe that these are the two options bc the other two aren't forsure sorry dude I'm trying :0

7 0

3 years ago

Pleaseeeee helpppppp

solong [7]

6x - 3.5 = -15.5
Add 3.5 to both sides
6x = -12
Divide by 6
x = -2
Carly has the correct response

8 0

2 years ago

Julia was creating similar triangles in the coordinate plane. The first triangle had a rise of 3 and a run of 10. The second tri

valina [46]

Yes julia is correct the run of the scond similar triangle will be b2=25.

<h3>What are simlilar traingles?</h3>

The similar triangle are those whose three sides or one angle or two sides or two angles one side are equal.

In the given:

Height of first triangle h=3

Base of first traingle =10

Height of second triangle =7.5

The base of second triangle b2 = ?

From the triangle similarity

$\dfrac{h_1}{b_1}=\dfrac{h_2}{b_2}$

$\dfrac{3}{10}=\dfrac{7.5}{b_2}$

$b_2=\dfrac{7.5\times 10}{3}$

$b_2=25$

Thus julia is correct the run of the scond similar triangle will be b2=25.

To know more about similar triangle follow

brainly.com/question/2644832

3 0

2 years ago

Consider three boxes with numbered balls in them. Box A con- tains six balls numbered 1, . . . , 6. Box B contains twelve balls

murzikaleks [220]

Answer:

a) 0.73684

b) 2/3

Step-by-step explanation:

part a)

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)}$

Using conditional probability as above:

(A,B,C)

Cases for numerator when:

P( A is 1 and exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1)

= $(\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) = 0.048611111$

Cases for denominator when:

P( Exactly two balls are 1) = P( 1, not 1, 1) + P(1, 1, not 1) + P(not 1, 1 , 1)

$= (\frac{1}{6}* \frac{11}{12}*\frac{1}{4}) + (\frac{1}{6}*\frac{1}{12}*\frac{3}{4}) + (\frac{5}{6}*\frac{1}{12}*\frac{1}{4})= 0.0659722222$

Hence,

$P ( A is 1 / exactly two balls are 1) = \frac{P ( A is 1 and that exactly two balls are 1)}{P (Exactly two balls are one)} = \frac{0.048611111}{0.06597222} \\\\= 0.73684$

Part b

$P ( B = 12 / A+B+C = 21) = \frac{P ( B = 12 and A+B+C = 21)}{P (A+B+C = 21)}$

Cases for denominator when:

P ( A + B + C = 21) = P(5,12,4) + P(6,11,4) + P(6,12,3)

$= 3*P(5,12,4 ) =3* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{96}$

Cases for numerator when:

P (B = 12 & A + B + C = 21) = P(5,12,4) + P(6,12,3)

$= 2*P(5,12,4 ) =2* \frac{1}{6}*\frac{1}{12}*\frac{1}{4}\\\\= \frac{1}{144}$

Hence,

$P ( B = 12 / A+B+C = 21) = \frac{\frac{1}{144} }{\frac{1}{96} }\\\\= \frac{2}{3}$

4 0

3 years ago

Find the minimum value of the parabola y = x2 + x .