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Anna71 [15]
3 years ago
12

Which expression is equal to -3b(6b^-8)

Mathematics
1 answer:
zimovet [89]3 years ago
4 0

Answer:a^2/b

Step-by-step explanation:

(a^6b^−3)1^/3

a^6 ^ 1/3  b ^ -3 ^ 1/3

using the power of power rule we can multiply the exponents

a ^ (6*1/3) b ^ (-3* 1/3)

a^ 2 b ^ -1

the negative exponent flips it from the numerator to the denominator

a^2* 1/ b^1

a^2/b

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Jeremy’s dad is making cupcakes for his birthday. He needs 50 cupcakes in all. So far he made 13 chocolate cupcakes and 15 vanil
Iteru [2.4K]

Answer:

22 cupcakes

Step-by-step explanation:

13+15=28

50-28=22

4 0
3 years ago
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Write an equation to find the amount of interest $450,000 earns in 1 year at a simple interest rate of 3.5%.
telo118 [61]

Answer:

The required equation for the amount of Simple Internet = \frac{450,000 \times 1 \times 3.5}{100}

Step-by-step explanation:

Here , Principal amount = $450,000

Time  = 1 year

Rate of Interest = 3.5%

Now,SIMPLE INTEREST  = \frac{P \times R \times T}{100}

So, here SI  = \frac{450,000 \times 1 \times 3.5}{100}

Hence, the required equation for the amount of Simple Internet = \frac{450,000 \times 1 \times 3.5}{100}

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4 years ago
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Find the gradient and y intercept of 3x+4y=5
noname [10]

Answer:

gradient = - \frac{3}{4} , y- intercept = \frac{5}{4}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

3x + 4y = 5 ( subtract 3x from both sides )

4y = - 3x + 5 ( divide terms by 4 )

y = - \frac{3}{4} x + \frac{5}{4} ← in slope- intercept form

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3 0
3 years ago
Help me answer these questions please 15, 19 and 20 please​
SpyIntel [72]

Answer:

15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

Step-by-step explanation:

We are to find the derivative of the questions pointed out.

15) K(t) = 5(5^(t)) - 2(3^(t))

Using implicit differentiation, we have;

K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]

19) P(w) = 2e^(w) - (2^(w))/5

P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]

20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)

Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)

Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)

7 0
3 years ago
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Jane's friend is wrong, the original price would be $200
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