Answer:
80,00
Step-by-step explanation:
According to my research, the formula for the Area of a rectangle is the following,

Where
- A is the Area
- L is the length
- W is the width
Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>
800 / 2 = 400ft
So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.
400/2 = 200 ft
Now we can calculate the maximum Area using the values above.


So the Maximum area we are able to create with 800 ft of fencing is 80,00
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Answer:
9 if I am correct also I rounded to a whole number, am not sure
Answer:
3.5
Step-by-step explanation:
6--1 = 7/2
= 3.5
Answer:
- (fog)(3) = f(g(3)) = f(12) = 60
Step-by-step explanation:
Given
Finding (fog)(x)
(fog)(x) = f(g(x))
(fog)(x) = f(x+9)
(fog)(x) = 5(x+9) ∵ substitute x as x+9 in the f(x)
(fog)(x) = 5x+45
Finding (gof)(x)
(gof)(x) = g(f(x))
(gof)(x) = g(5x)
(gof)(x) = 5x+9 ∵ substitute x as 5x in the g(x)
Finding (fog)(3)
(fog)(3) = f(g(3))
substitute x = 3 in the g(x)=x+9
g(x) = x+9
g(3) = 3+9
g(3) = 12
so
(fog)(3) = f(g(3)) = f(12)
now substitute x = 12 in f(x) = 5x
f(x) = 5x
f(12) = 5(12)
f(12) = 60
Thus,
(fog)(3) = f(g(3)) = f(12) = 60