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eimsori [14]
3 years ago
5

Suppose 30% of OSU students watch reality TV shows of some kind every week. 100 OSU students are selected at random and asked if

they watch reality TV of some kind each week.
X = number in the sample who watch reality TV of some kind each week.
Find the mean and SD of X.
Mathematics
1 answer:
andrey2020 [161]3 years ago
3 0

Answer:

Step-by-step explanation: and true

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146, 74, 38, 20, ? what would the next number be in this sequence?
Anuta_ua [19.1K]
Looking at the numbers, we can see that the differences are 72, 36, and 18. Notice that they are each factors of the next by the same constant 2.

18 * 2 = 36
36 * 2 = 72

There, it means that 18/2 will be subtracted from 20.

20 - 18/2
= 20 - 9
= 11

The next number in the sequence would be 11. Hope this helps!
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What is the constant of proportionality in the equation?<br><br> y = 5 x<br> 0<br> 1<br> 4<br> 5
AleksandrR [38]

Answer:

D.) 5

Step-by-step explanation:

5 is the constant  proportionality in the equation; y = 5 x

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Julia is using the distributive property to simplify 3(x+2). Find her mistake and correct it
dusya [7]
3x + 6
distribute the 3 to both of the places in the parentheses. 
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If the points (0, 0), (-1, 1), and (-2, 2) lie on the graph of function h, then which of the following rules could represent the
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Lines k and n intersect on the y-axis
avanturin [10]

a) The equation of line k is:

y = -\frac{202}{167}x + \frac{598}{167}

b) The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

The equation of a line, in <u>slope-intercept formula</u>, is given by:

y = mx + b

In which:

  • m is the slope, which is the rate of change.
  • b is the y-intercept, which is the value of y when x = 0.

Item a:

  • Line k intersects line m with an angle of 109º, thus:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

In which m_1 and m_2 are the slopes of <u>k and m.</u>

  • Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}

  • The tangent of 109 degrees is \tan{109^{\circ}} = -\frac{29}{10}
  • Thus, the slope of line m is found solving the following equation:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}

m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2

m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}

\frac{167m_2}{80} = \frac{-202}{80}

m_2 = -\frac{202}{167}

Thus:

y = -\frac{202}{167}x + b

It goes through point (-2,6), that is, when x = -2, y = 6, and this is used to find b.

y = -\frac{202}{167}x + b

6 = -\frac{202}{167}(-2) + b

b = 6 - \frac{404}{167}

b = \frac{6(167)-404}{167}

b = \frac{598}{167}

Thus. the equation of line k, in slope-intercept formula, is:

y = -\frac{202}{167}x + \frac{598}{167}

Item b:

  • Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

-\frac{202}{167}m = -1

m = \frac{167}{202}

Then

y = \frac{167}{202}x + b

Also goes through point (-2,6), thus:

6 = \frac{167}{202}(-2) + b

b = \frac{(2)167 + 202(6)}{202}

b = \frac{1546}{202}

The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

A similar problem is given at brainly.com/question/16302622

7 0
2 years ago
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