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3 years ago

12

of 200 guests invited to a wedding, 154 attended the wedding. what percent of the invited guests attended the wedding?

1 answer:

horsena [70]3 years ago

4 0

Answer:

77% of the invited guests attended the wedding.

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The Difference of 4 and k, divided by 16.

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Answer:4-k÷6

Step-by-step explanation:

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2 years ago

Complete the similarity statement for the two given triangles.

tino4ka555 [31]

The comment on top of me is a virus don’t go on it

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2 years ago

What transformation is represented by the rule (x, y)→(−y, x) ?

Andrej [43]

the answer is C. Reflection across the X-axis

Hope this helps!

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3 years ago

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Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spen

ICE Princess25 [194]

A.
s=number of strawberry wafers
c=number of chocolate wafers

3s+1c=30
s+c=22

B.
multiply 2nd equation by -1 to do elimination
add to the first equation

3s+1c=30
<u>-s-c=-22 +</u>
2s+0c=8

2s=8
divide by 2
s=4

sub back
s+c=22
4+c=22
c=18

I used elimiation because it seemed right for this one

I can also do subsitution

3s+1c=30
s+c=22
minus s both sides in 2nd equation

c=22-s
sub for c in other equation
3s+22-s=30
2s+22=30
minus 22 both sides
2s=8
divide by 2
s=4
and now
c=22-s
c=22-4
c=18

substiotion because it's easier for some people to see

18 chocolate
4 strawberry

5 0

3 years ago

Which equation represents a graph with a vertex at (–3, 2)?

lesya [120]

<u>We will proceed to find the equations in the vertex form in each case</u>

<u>Part a)</u> $y= 4x^{2}+24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}+24x$

Factor the leading coefficient

$y-38= 4(x^{2}+6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}+6x+9)$

$y-2= 4(x+3)^{2}$

$y= 4(x+3)^{2}+2$

<u>the vertex is the point $(-3,2)$ </u>

<u>Part b)</u> $y=4x^{2}-24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}-24x$

Factor the leading coefficient

$y-38= 4(x^{2}-6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}-6x+9)$

$y-2= 4(x-3)^{2}$

$y= 4(x-3)^{2}+2$

<u>the vertex is the point $(3,2)$ </u>

<u>Part c) </u> $y=4x^{2}+12x+2$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-2= 4x^{2}+12x$

Factor the leading coefficient

$y-2= 4(x^{2}+3x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-2+9= 4(x^{2}+3x+2.25)$

$y+7= 4(x+1.5)^{2}$

$y= 4(x+1.5)^{2}-7$

<u>the vertex is the point $(-1.5,7)$ </u>

<u>Part d)</u> $y=4x^{2}+16x+13$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-13= 4x^{2}+16x$

Factor the leading coefficient

$y-13= 4(x^{2}+4x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-13+16= 4(x^{2}+4x+4)$

$y+3= 4(x+2)^{2}$

$y= 4(x+2)^{2}-3$

<u>the vertex is the point $(-2,-3)$ </u>

therefore

<u>the answer is </u>

$y= 4x^{2}+24x+38$

3 0

3 years ago

Read 2 more answers