Answer:
B is the answer 12x^3 - 6x^2 +6x +8
Step-by-step explanation:
H0: u = 150
H1: u ≠ 150
Total sum = 15933.24
N = 100
Mean = 15933.24/100
= 159.3324
σ² = 25954.03 - (159.3324)²/100
σ² = 556.213
σ = √556.213
σ = 23.8162
Testing hypothesis
t = (bar x - u)/ σ/√n
= 159.3324-150/23.8162/√100
= 3.91
We will have a p value of 0.02
0.0002 < 0.01
We reject null hypothesis at 1% level of significance
C. Mean = 159.3324
Se= 2.3936
Df = 100-1 = 99
Critical value at 0.01 = +-2.626
T = x-u/s.e
= -2.626 =( x -150)/2.3936
When we cross multiply and solve this
X = 143.714 for the lower tail
2.626 = (x-159)/2.3936
= 156.286 for upper tail.
We therefore reject H0 at
Bar X <= 143.71
Bar X >= 156.286
At 10%
Critical t = 1.660
-1.660 = (x - 150)/2.3936
Solving this ,
X =146.02 at the lower tail
1.660 = (x-150)/2.3936
X = 153.97
We reject H0 at
X<= 146.03
X>=153.97
Call the output f(x)
Call the input x
f(x) = x - 3
Answer:
y = -2/3x+3
Step-by-step explanation:
Slope = y2-y1/x2-x1
(3,1) = (x1,y1)
(9,-3) = (x2,y2)
Slope = (-3-1)/(9-3)
= -4/6
= -2/3
y-intercept form: y=mx+b [m=slope, b=y-intercept]
plugging (3,1) into this 1 = -2/3×3 +b
1 = -2 +b
b = 3
The area of the kite can be found as follows;
Area=[area of XWY]+[areaYWZ]
area XWY=1/2*b*h
=1/2*4*3=6 sq units
area YWZ=1/2*b*h
=1/2*4*4=8 sq units
Hence the area of the kite will be:
Area=6+8=14 sq. units